rank points player_id quiz_id
1 88 1 40
2 80 3 40
3 30 3 41
4 20 1 41
从以下查询中获取此输出:
SELECT m.rank,
m.scorer AS points,
m.player_id
FROM
( SELECT d.player_id,
d.scorer, @rownum := @rownum + 1 AS rank
FROM
( SELECT t.player_id,
SUM(t.score) AS scorer
FROM answers t
JOIN PROFILE ON profile.player_id = t.player_id
JOIN quiz ON t.quiz_id = quiz.id
WHERE t.is_active = 1
AND quiz.contest_id = 1
AND profile.signin_source_id != 1
AND profile.is_active = 1
AND t.quiz_id IN (1,
2)
GROUP BY t.player_id
ORDER BY scorer DESC, t.created_utc ASC) d,
(SELECT @rownum := 0) r) m
WHERE m.scorer > 0
但是,我想要的输出是将每个级别分开的排名。
rank points player_id quiz_id
1 88 1 40
2 80 3 40
1 30 3 41
2 20 1 41
我关注了这些:
How to perform grouped ranking in MySQL
却得不到想要的输出。任何建议或帮助表示赞赏。
最佳答案
试试这个查询,IMO 更简单:
select @quiz_id_lag := 0, @rank := 1;
select rank, points, player_id, quiz_id from (
select points,
player_id,
case when @quiz_id_lag = quiz_id then @rank := @rank + 1 else @rank := 1 end rank,
@quiz_id_lag,
@quiz_id_lag := quiz_id,
quiz_id
from tbl
order by quiz_id, points desc
) a;
要将其合并到您的查询中,请尝试:
SELECT @quiz_id_lag := 0, @rank := 1;
SELECT rank,
scorer AS points,
player_id
FROM (
SELECT quiz_id,
player_id,
scorer,
CASE WHEN @quiz_id_lag = quiz_id THEN @rank := @rank + 1 ELSE @rank := 1 END rank,
@quiz_id_lag := quiz_id,
quiz_id
FROM (
SELECT t.player_id,
SUM(t.score) AS scorer,
t.quiz_id
FROM answers t
JOIN PROFILE ON profile.player_id = t.player_id
JOIN quiz ON t.quiz_id = quiz.id
WHERE t.is_active = 1 AND quiz.contest_id = 1 AND profile.signin_source_id != 1
AND profile.is_active = 1 AND t.quiz_id IN (1, 2)
GROUP BY t.player_id
) d
WHERE scorer > 0
ORDER BY quiz_id, scorer DESC
) m
关于Mysql Group By Levels排名,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51785361/