我有一些从网站上抓取的项目,我将它们放入 json 文件中,如下所示
{
"author": ["TIM ROCK"],
"book_name": ["Truk Lagoon, Pohnpei & Kosrae Dive Guide"],
"category": "Travel",
}
{
"author": ["JOY"],
"book_name": ["PARSER"],
"category": "Accomp",
}
我想将它们存储在 csv 文件中,每行一个字典,其中每列一个项目,如下所示
| author | book_name | category |
| TIM ROCK | Truk Lagoon ... | Travel |
| JOY | PARSER | Accomp |
我将一本字典的项目放在一行中,但将所有列组合在一起
我的pipeline.py
代码是
导入csv
class Blurb2Pipeline(object):
def __init__(self):
self.brandCategoryCsv = csv.writer(open('blurb.csv', 'wb'))
self.brandCategoryCsv.writerow(['book_name', 'author','category'])
def process_item(self, item, spider):
self.brandCategoryCsv.writerow([item['book_name'].encode('utf-8'),
item['author'].encode('utf-8'),
item['category'].encode('utf-8'),
])
return item
最佳答案
要点是,使用 csv.DictWriter
非常简单:
>>> inputs = [{
... "author": ["TIM ROCK"],
... "book_name": ["Truk Lagoon, Pohnpei & Kosrae Dive Guide"],
... "category": "Travel",
... },
... {
... "author": ["JOY"],
... "book_name": ["PARSER"],
... "category": "Accomp",
... }
... ]
>>>
>>> from csv import DictWriter
>>> from cStringIO import StringIO
>>>
>>> buf=StringIO()
>>> c=DictWriter(buf, fieldnames=['author', 'book_name', 'category'])
>>> c.writeheader()
>>> c.writerows(inputs)
>>> print buf.getvalue()
author,book_name,category
['TIM ROCK'],"['Truk Lagoon, Pohnpei & Kosrae Dive Guide']",Travel
['JOY'],['PARSER'],Accomp
最好将这些数组连接到某些东西上,但由于元素可以是列表或字符串,所以有点棘手。判断某个东西是字符串还是其他可迭代对象是 Python 中直接类型检查很有意义的少数情况之一。
>>> for row in inputs:
... for k, v in row.iteritems():
... if not isinstance(v, basestring):
... try:
... row[k] = ', '.join(v)
... except TypeError:
... pass
... c.writerow(row)
...
>>> print buf.getvalue()
author,book_name,category
TIM ROCK,"Truk Lagoon, Pohnpei & Kosrae Dive Guide",Travel
JOY,PARSER,Accomp
关于python - 在scrapy python中的一行csv文件中每列排列一个项目,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/10816241/