我正在使用django-relationships我正在按关注者数量过滤我的用户,如下所示:
Relationship.objects.values('to_user').annotate(num_followers=Count('to_user')).order_by('-num_followers')
返回类似这样的内容
[{'to_user': 1, 'num_followers': 3}, {'to_user': 4, 'num_followers': 1}]
我的问题是我需要访问我的 User 对象,而不仅仅是他们的 pk
。现在我正在做这样的事情:
tu_list = []
for tu in top_users_set:
tu_list.append({
'top_user': User.objects.get(pk=tu['to_user']),
'followers': tu['num_followers'],
})
它正在为每个用户进行查询。由于查询集最终可能有数百个以上的用户,这可能非常糟糕。
任何有助于改进这一点的意见将不胜感激。
谢谢
最佳答案
如果您想要用户,您需要通过查询用户模型并加入关系来以相反的方式访问它。这是相关的documentation
应该是这样的:
from django.db.models import Count
users = User.objects.annotate(num_followers=Count('to_users')).order_by('-num_followers')
这将为您提供用户,并且每个用户都将拥有一个额外的属性num_followers
model.py
from django.contrib.auth.models import User
from django.db import models
class Relationship(models.Model):
from_user = models.ForeignKey(User, related_name='from_users')
to_user = models.ForeignKey(User, related_name='to_users')
测试
>>> from so.models import *
>>> from django.contrib.auth.models import User
>>> u1 = User()
>>> u1.username='user1'
>>> u1.save()
>>> u2 = User()
>>> u2.username='user2'
>>> u2.save()
>>> u3=User()
>>> u3.username='user3'
>>> u3.save()
>>> # so we have 3 users now
>>> r1 = Relationship()
>>> r1.from_user=u1
>>> r1.to_user=u2
>>> r1.save()
>>> r2=Relationship()
>>> r2.from_user=u1
>>> r2.to_user=u3
>>> r2.save()
>>> r3=Relationship()
>>> r3.from_user=u2
>>> r3.to_user=u3
>>> r3.save()
>>> rels = Relationship.objects.all()
>>> rels.count()
3
>>> # we have 3 relationships: user1 follows user2, user1 follows user3, user2 follows user3
>>> users = User.objects.annotate(num_followers=Count('to_users')).order_by('-num_followers')
>>> for user in users:
>>> print user.username, user.num_followers
user3 2
user2 1
user1 0
EDIT2修复了拼写错误,添加了测试
关于python - Django - 在带注释的查询中访问外键数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11140628/