(编号为 2-10 的牌的点数应分别为 2-10。J、Q 和 K 应为 10,A 应为 1 或 11,具体取决于手牌的点数)。
如何为牌组分配这些值?另外,比赛需要进行3轮。我的方法只有一轮。如何让游戏进行三次,同时跟踪玩家的输赢?
有人可以解释一下我如何以简单的方式做到这一点吗?
最佳答案
这是为您提供的完整实现
看手牌。分数
import random
class Card:
def __init__(self,rank,suite):
self.rank = rank
self.suite = suite
def Rank(self):
return "Ace Two Three Four Five Six Seven Eight Nine Ten Jack Queen King".split()[self.rank]
def Suite(self):
return "Hearts Spades Clubs Diamonds".split()[self.suite]
def __str__(self):
#print "Get Self:",type(self)
#print "Dir:",dir(self)
#return "OF"
return self.Rank()+" of "+ self.Suite()
class Hand:
def __init__(self):
self.cards = []
def Score(self):
aces_ct = 0
score = 0
for c in self.cards:
if c.rank == 0:
aces_ct += 1
score += 11
if 0 < c.rank < 9:
score += c.rank+1
else:
score += 10
while score > 21 and aces_ct > 0:
score -= 10
aces_ct -= 1
return score
def add(self,card):
self.cards.append(card)
def Show(self,show_only=None):
if not show_only:
for k in self.cards:
print "%s"%k
else:
if isinstance(show_only,int):
print "%s"%self.cards[show_only]
elif isinstance(show_only,(list,tuple)):
for idx in show_only:
print "%s"%self.cards[idx]
class deck:
def __init__(self):
self.cards = []
for i in range(4):
for j in range(13):
self.cards.append(Card(j,i))
random.shuffle(self.cards)
def shuffle(self):
random.shuffle(self.cards)
def pop(self):
return self.cards.pop()
if __name__ == "__main__":
d = deck()
player_hand = Hand()
dealer_hand = Hand()
player_hand.add(d.pop())
dealer_hand.add(d.pop())
player_hand.add(d.pop())
dealer_hand.add(d.pop())
print "Player Score :",player_hand.Score()
player_hand.Show()
print "\n\nDealer Score :",dealer_hand.Score()
dealer_hand.Show()
关于python - 无法为一副牌赋予数值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11730723/