基本上,我希望有一个列表,显示我存储在某个文件夹中的文件,列表旁边有一些按钮,可以打开单独的窗口,可以编辑该列表或向该列表添加新项目。
我希望 addchar 打开一个新窗口,其中包含不同字段的空格,然后当您在该窗口中按下“创建”按钮时,它会关闭,根据您刚刚输入的信息创建一个文件(这就是我导入 os 的原因) )以及在主界面的列表框中创建一个新项目作为角色名称(这是字段之一)。 removechar 函数将删除该条目并删除文件,而 editchar 将打开一个类似于 addchar 的窗口,但包含列表中所选项目的信息。
编辑:这是到目前为止的代码
from tkinter import *
import os
import easygui as eg
class App:
def __init__(self, master):
frame = Frame(master)
frame.pack()
# character box
Label(frame, text = "Characters Editor").grid(row = 0, column = 0, rowspan = 1, columnspan = 2)
charbox = Listbox(frame)
for chars in []:
charbox.insert(END, chars)
charbox.grid(row = 1, column = 0, rowspan = 5)
charadd = Button(frame, text = " Add ", command = self.addchar).grid(row = 1, column = 1)
charremove = Button(frame, text = "Remove", command = self.removechar).grid(row = 2, column = 1)
charedit = Button(frame, text = " Edit ", command = self.editchar).grid(row = 3, column = 1)
def addchar(self):
print("not implemented yet")
def removechar(self):
print("not implemented yet")
def editchar(self):
print("not implemented yet")
root = Tk()
root.wm_title("IA Development Kit")
app = App(root)
root.mainloop()
最佳答案
好的,我为您实现了 addchar
和 removechar
(并在您的代码中调整了一些其他内容)。我将把 editchar
的实现留给您 - 看看我写的内容来帮助您,以及 listbox documentation
from Tkinter import * # AFAIK Tkinter is always capitalized
#import os
#import easygui as eg
class App:
characterPrefix = "character_"
def __init__(self, master):
self.master = master # You'll want to keep a reference to your root window
frame = Frame(master)
frame.pack()
# character box
Label(frame, text = "Characters Editor").grid(row = 0, column = 0, rowspan = 1, columnspan = 2)
self.charbox = Listbox(frame) # You'll want to keep this reference as an attribute of the class too.
for chars in []:
self.charbox.insert(END, chars)
self.charbox.grid(row = 1, column = 0, rowspan = 5)
charadd = Button(frame, text = " Add ", command = self.addchar).grid(row = 1, column = 1)
charremove = Button(frame, text = "Remove", command = self.removechar).grid(row = 2, column = 1)
charedit = Button(frame, text = " Edit ", command = self.editchar).grid(row = 3, column = 1)
def addchar(self, initialCharacter='', initialInfo=''):
t = Toplevel(root) # Creates a new window
t.title("Add character")
characterLabel = Label(t, text="Character name:")
characterEntry = Entry(t)
characterEntry.insert(0, initialCharacter)
infoLabel = Label(t, text="Info:")
infoEntry = Entry(t)
infoEntry.insert(0, initialInfo)
def create():
characterName = characterEntry.get()
self.charbox.insert(END, characterName)
with open(app.characterPrefix + characterName, 'w') as f:
f.write(infoEntry.get())
t.destroy()
createButton = Button(t, text="Create", command=create)
cancelButton = Button(t, text="Cancel", command=t.destroy)
characterLabel.grid(row=0, column=0)
infoLabel.grid(row=0, column=1)
characterEntry.grid(row=1, column=0)
infoEntry.grid(row=1, column=1)
createButton.grid(row=2, column=0)
cancelButton.grid(row=2, column=1)
def removechar(self):
for index in self.charbox.curselection():
item = self.charbox.get(int(index))
self.charbox.delete(int(index))
try:
os.remove(characterPrefix + item)
except IOError:
print "Could not delete file", characterPrefix + item
def editchar(self):
# You can implement this one ;)
root = Tk()
root.wm_title("IA Development Kit")
app = App(root)
root.mainloop()
关于python - 如何在 Python 的 Tkinter 中制作一个交互式列表,并包含可以编辑这些列表的按钮?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18201195/