python - Python中递归打印文件目录

Question

我试图弄清楚如何以正确的缩进打印目录中的每个项目。到目前为止我的代码如下:

import os

def traverse(pathname,d):
    'prints a given nested directory with proper indentation'
    indent = ''
    for i in range(d):
        indent = indent + '  '
    for item in os.listdir(pathname):
        try:
            newItem = os.path.join(pathname, item)
            traverse(newItem,d+1)
        except:
            print(indent + newItem)

我的输出打印出测试目录中的所有文件，但不打印文件夹名称。我得到的是这样的:

>>> traverse('test',0)
test/fileA.txt
  test/folder1/fileB.txt
  test/folder1/fileC.txt
    test/folder1/folder11/fileD.txt
  test/folder2/fileD.txt
  test/folder2/fileE.txt
>>>

输出应该是什么:

>>> traverse('test',0)
test/fileA.txt
test/folder1
  test/folder1/fileB.txt
  test/folder1/fileC.txt
  test/folder1/folder11
    test/folder1/folder11/fileD.txt
test/folder2
  test/folder2/fileD.txt
  test/folder2/fileE.txt
>>>

谁能让我知道我需要用代码做什么才能显示文件夹名称？我尝试打印出路径名，但每次 Python 打印出文件名时，它都会重复文件夹名称，因为它处于 for 循环中。如果能朝正确的方向插入，我们将不胜感激!

Answer 1

无论是否是目录，您都需要打印文件名，例如:

for item in os.listdir(pathname):
    try:
        newItem = os.path.join(pathname, item)
        print(indent + newItem)
        traverse(newItem,d+1)
    except:
        pass

虽然我不想使用异常来检测它是否是一个目录，所以如果允许os.path.isdir:

for item in os.listdir(pathname):
    newItem = os.path.join(pathname, item)
    print(indent + newItem)
    if (os.path.isdir(newItem)):
        traverse(newItem,d+1)