python - 当表单有标点符号时引发错误 django

Question

当有人提交标题中带有标点符号的内容时，我需要一种方法来引发错误。我是初学者，所以不太确定该怎么做。
形式:

class NeededForm(forms.ModelForm):
    title = forms.CharField(max_length=120)
    likes = forms.IntegerField(widget=forms.HiddenInput(), initial=0)
    body = forms.CharField(min_length=50,widget = forms.Textarea)
    captcha = CaptchaField()

    def clean_title(self):
        data = self.cleaned_data['title']
        return data
    class Meta:
        model = Needed
        fields = ('title', 'body', 'likes')

View :

def detail(request, needed_title_url):
    context = RequestContext(request)

    needed_name = needed_title_url.replace('_', ' ')
    context_dict = {'needed_name': needed_name}
    try:
        needed = Needed.objects.get(title=needed_name)
        context_dict['needed'] = needed
        print "True!"
    except:
        pass

    return render_to_response('needed.html', context_dict, context)

如果用户输入类似:I like Chicken! 作为标题，那么我需要向用户显示错误。

Answer 1

我不太确定能明白你的问题，但看起来你正在寻找的答案可能包含在 https://docs.djangoproject.com/en/1.6/ref/models/fields/#slugfield 中

SlugField 是一个CharField，只能包含字母、数字、下划线和连字符(因此它可以理解max_length，...)

class NeededForm(forms.ModelForm):
    title = forms.SlugField(max_length=120)
    likes = forms.IntegerField(widget=forms.HiddenInput(), initial=0)
    body = forms.CharField(min_length=50,widget = forms.Textarea)
    captcha = CaptchaField()

如果您正在寻找更复杂的规则检查，请查看验证器页面 https://docs.djangoproject.com/en/1.6/ref/validators/以及如何在表单中使用它 https://docs.djangoproject.com/en/1.6/ref/forms/validation/#using-validators 提供的示例解释了 SlugField 实现。

希望对你有帮助!