我有一本字典，里面有 400,000 个项目，其键是 DNA 名称，值是 DNA 序列。 我想将字典分成 40 个文本文件，每个文件中有 10,000 个项目。
这是我的代码:
record_dict # my DNA dictionary
keys_in_dict #the list of the keys
for keys in keys_in_dict:
outhandle = open("D:\\Research\\Transcriptome_sequences\\input{0}.fasta".format (?????), "w")
我应该用什么来代替 (??????)？我该如何完成这个循环？
更新: 嘿伙计们， 感谢您的帮助。现在我可以从字典中创建多个文件。但是，当我尝试直接从原始文件创建多个文件而不是先创建字典时，我遇到了问题。这些代码仅生成一个包含第一项的文件。我做错了什么？这是我的代码:
from Bio import SeqIO
handle = open("D:/Research/Transcriptome_sequences/differentially_expressed_genes.fasta","rU")
filesize = 100 # number of entries per file
filenum = 0
itemcount = 0
for record in SeqIO.parse(handle, "fasta") :
if not itemcount % filesize:
outhandle = open("D:/Research/Transcriptome_sequences/input{0}.fasta".format(filenum), "w")
SeqIO.write(record, outhandle, "fasta")
filenum += 1
itemcount += 1
outhandle.close()
最佳答案
n = 10000
sections = (record_dict.items()[i:i+n] for i in xrange(0,len(record_dict),n))
for ind, sec in enumerate(sections):
with open("D:/Research/Transcriptome_sequences/input{0}.fasta".format(ind), "w") as f1:
for k,v in sec:
f1.write("{} {}\n".format(k,v))
关于python - 如何在Python中从字典写入多个文件，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/26856026/