python - 如何在这段Python代码中迭代元组？

Question

我有一个包含如下元组列表的文件:

(1, 4)

(569, 39)

(49, 69)

。 。 .

我有这个代码，但同时读取所有行，我只想读取行，例如第1行，并将值x,y设置在函数中，然后返回第2行并取值 x、y，然后再次执行，当我的文件长度完成时停止。

我可以在代码中更改什么来返回下一行？

import ast

def readfile():
     filename = open('file.log')
     result=[]


     with open('file.log', 'r') as f:
          lst = [ast.literal_eval(line) for line in f.readlines()]

     for t in lst:
          x, y = t
          for t in [(x,y) for x in t[0:] for y in t[:1]]:
               print x, y
               value = (x, y)

               result.append(value)

     return result[1:-1]

print readfile()

Answer 1

my end goal is: take the values x, y, of the line 1 and use them in other function, when this function is done, return the line 2 and take other values for do it again, and stop when my lenght of my file is done.

听起来您想要一个从文件中迭代生成值的函数。示例实现:

import ast

def readfile():
    with open('file.log', 'r') as f:
        for line in f:
            yield ast.literal_eval(line)

def do_something(a,b):
    print "I am doing something with {} and {}".format(a,b)

for x,y in readfile():
    do_something(x,y)

结果:

I am doing something with 1 and 4
I am doing something with 569 and 39
I am doing something with 49 and 69