我正在尝试找出如何让该函数显示异常
clone_saved_path():
def clone_saved_path():
except OSError as e:
# If the error was caused because the source wasn't a directory
print('Directory not copied. Error: %s' % e)
print("got here. [4]")
except:
print("Another error occurred in clone_saved_path() ")
print("got here. [5]")
当我运行代码时,它会命中最后一个 except
block 并输出:
print("Another error occurred in clone_saved_path() ")
我知道这听起来可能很基础,但我需要弄清楚如何显示实际异常。
最佳答案
https://docs.python.org/3/library/sys.html#sys.exc_info
“此函数返回一个包含三个值的元组,其中提供有关当前正在处理的异常的信息。”
所以你可以执行如下操作(此处建议:https://docs.python.org/3/tutorial/errors.html#handling-exceptions):
import sys
# ...
except:
print("Another error occurred in clone_saved_path() ")
print(sys.exc_info()[0]) # type of exception
raise
关于python - 在clone_saved_path()中捕获异常,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31343494/