python - 如何正确循环这段代码？我无法让它工作。对编码还很陌生

Question

import random

randomOne = random.randint(1,10)
    print(randomOne)
randomTwo = random.randint(1,10)
    print(randomTwo)

b = randomTwo * 2
while b != randomOne:
    print("Your first number is not a multiple of the second number!")
x = input('Press Enter to try again.')


randomOne = random.randint(1,10)
print(randomOne)
randomTwo = random.randint(1,10)
print(randomTwo)

if randomTwo * 2 == randomOne:
    print("Your first number is a multiple of the second number!")

当第二个数字不是第一个数字的倍数时，我无法循环此代码。另外，如何使程序在条件为真时完成，即第二个数字是第一个数字的倍数。

Answer 1

与大多数其他编程语言不同，Python 中代码缩进很重要。由于缩进已修复，以下内容应该有效。此外，您还需要在 while 循环中重新计算 b 的值，这样循环最终会失败。

import random

randomOne = random.randint(1,10)
print(randomOne)
randomTwo = random.randint(1,10)
print(randomTwo)

b = randomTwo * 2
while b != randomOne:
    print("Your first number is not a multiple of the second number!")
    x = input('Press Enter to try again.')

    randomOne = random.randint(1,10)
    print(randomOne)
    randomTwo = random.randint(1,10)
    print(randomTwo)
    b = randomTwo * 2

# No need to check if it is a multiple since it must be to break the loop
print("Your first number is a multiple of the second number!")

如果您的目标是找到两个数字的组合，其中第一个数字实际上是第二个数字的倍数，您可以尝试如下操作:

import random

randomOne = random.randint(1,10)
print(randomOne)
randomTwo = random.randint(1,10)
print(randomTwo)

b = randomOne / randomTwo
# If b is an integer, then it divided evenly
while b != int(b):
    print("Your first number is not a multiple of the second number!")
    x = input('Press Enter to try again.')

    randomOne = random.randint(1,10)
    print(randomOne)
    randomTwo = random.randint(1,10)
    print(randomTwo)
    b = randomOne / randomTwo

if randomTwo * 2 == randomOne:
    print("Your first number is a multiple of the second number!")