我的任务是创建一个程序来检测外国和超速的车牌。为此,必须创建一段道路、耗时等。代码的问题不在于速度有多不切实际,而是事实上我最近从老师那里发现速度应该以英里每小时为单位,而不是米每秒。
import re
# DATA
distance = 0.06 # Distance between the Camera A and B; 0.06 = 600 metres
speed_limit = 20 # (meters per second)
number_plates = ["DV61 GGB", #UK
"D31 EG 2A", #F
"5314 10A02", #F
"24TEG 5063", #F
"TR09 TRE", #UK
"524 WAL 75", #F
"TR44 VCZ", #UK
"FR52 SWD", #UK
"100 GBS 12", #F
"HG55 BPO" #UK
]
enter = [7.12,7.17,7.22,7.12,7.23,7.41,7.18,7.25,7.11,7.38]
leave = [7.56,7.39,7.49,7.56,7.45,7.57,7.22,7.31,7.59,7.47]
# Find the non-UK plates
pattern = "(?![A-Z]{2}\d{2}\s+[A-Z]{3}$)"
foreign_numbers = list(filter(lambda x: re.match(pattern, x), number_plates))
# Calculations for speed
elapsed = [(l - e)/100 for l, e in zip(leave, enter)]
speed = [distance/t for t in converted_elapsed]
# Dictionary for foreign speeders + 2 conditions
foreign_speeders = {plate: speed
for plate, speed in zip(number_plates, speed)
if (plate in foreign_numbers) and (speed > speed_limit)}
print("10 cars have passed Camera A, then Camera B\nSpeed limit is 20 meters per second.\n")
# Write foreign speeders to file
for plate, speed in foreign_speeders.items():
speeders_data = open("speeders.txt","w") # Opens file with name of "speeders.txt"
speeders_data.write(
"{0:>13s} is foreign and is speeding at{1:5.1f} mps, and has an excess speed of {2:3.1f} mps.".format(plate, speed, speed-speed_limit))
speeders_data = open("speeders.txt","r")
print(speeders_data.read())
speeders_data.close()
我想知道,重写所有速度变量是否更简单,例如speed_limit
和elapsed
项以及speed
公式> 以它们转换的形式,或者在代码中间转换速度?
哪种解决方案更合适,我该怎么做?
最佳答案
首先,您肯定需要一个可以转换单位的函数,例如mps_to_mph
按照@mirosval 的建议。
但是,我建议您应该在某个时候更清楚地说明单位是什么。
最简单的解决方案是将其放在变量名中:speed_mps = 78.7
,speed_mph = mps_to_mph(speed_mps)
,否则当你再次阅读代码时将无法理解你的代码(好吧,你可能永远不会再读这段代码,但至少你的老师会......并且你写的每一个代码都应该很容易理解,不需要额外的解释)。
在更复杂的应用程序中,有许多这样的计算,您可能希望有一个可以记住单位并知道如何转换值的类,以便您可以执行以下操作:
speed = Speed(78.8, 'm/s')
if speed > Speed(60, 'mph'):
# something
关于python - 如何在代码中转换速度?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34202554/