python - 将变量分配给列表项python

Question

我正在寻找一种通过具有相同的 .这是我的代码来启发事物。

    count = 0
    beer = 5/100
    maltbeer = 7/100
    tablewine = 12/100
    fortifiedwine = 17/100
    aperitif = 24/100
    spirits = 40/100
    percentageCalc = 0
    for i in drinks:
        count =+ 1
        percentageCalc = percentageCalc + drinks[count]

饮料被输入到饮料中，并且可能会根据输入的内容而变化。

即:饮料 = ['啤酒', '啤酒', '烈酒', '麦芽啤酒']

饮料是 append 输入，仅接受作为进一步看到的变量之一。

Answer 1

使用各种饮料的字典:

abv = {"beer": 5
       "maltbeer": 7,
       "tablewine": 12,
       "fortifiedwine": 17,
       "aperitif": 24,
       "spirits": 40}

percentage = 0

for drink in drinks:
    if drink in abv:
        percentage += percentageCalc + abv[drink]
    else:
        print("don't know about %s" % drink)

percentage /= 100.0

我还从各个项目中删除了 /100 计算并添加到最后，并在不知道饮料的情况下实现了错误消息。