我有几个数据帧 df1、df2...,其中包含重复的数据、部分重叠的列和行((见下文)
如何将所有数据帧集中到一个数据帧中。
df1 = pd.DataFrame({'A': [1,2], 'B': [4,5]}, index=['a', 'b'])
df2 = pd.DataFrame({'B': [5,6], 'C': [8,9]}, index=['b', 'c'])
df3 = pd.DataFrame({'A': [2,3], 'B': [5,6]}, index=['b', 'c'])
df4 = pd.DataFrame({'C': [7,8], index=['a', 'b'])
df5 = pd.DataFrame({'A': [1], 'B': [4], 'C': [7]}, index=['a'])
....
添加:示例数据结构
A B C
a 1 4 7
b 2 5 8
c 3 6 9
补充:我真正寻找的是以下脚本的更有效方法,这对于大数据帧来说确实很慢
dfs =[df1, df2, df3, df4, df5]
cols, rows = [], []
for df in dfs:
cols = cols + df.columns.tolist()
rows = rows + df.index.tolist()
cols = np.unique(cols)
rows = np.unique(rows)
merged_dfs = pd.DataFrame(data=np.nan, columns=cols, index=rows)
for df in dfs:
for col in df.columns:
for row in df.index:
merged_dfs[col][row] = df[col][row]
快速简单的解决方案(2015 年 23 月 23 日添加)
dfs =[df1, df2, df3, df4, df5]
# create empty DataFrame with all cols and rows
cols, rows = [], []
for df_i in dfs:
cols = cols + df_i.columns.tolist()
rows = rows + df_i.index.tolist()
cols = np.unique(cols)
rows = np.unique(rows)
df = pd.DataFrame(data=np.NaN, columns=cols, index=rows)
# fill DataFrame
for df_i in dfs:
df.loc[df_i.index, df_i.columns] = df_i.values
最佳答案
具有索引保存
这是保留索引的更新版本:
from functools import reduce
dfs = [df1, df2, df3, df3, df5]
def my_merge(df1, df2):
res = pd.merge(df1, df2, how='outer', left_index=True, right_index=True)
cols = sorted(res.columns)
pairs = []
for col1, col2 in zip(cols[:-1], cols[1:]):
if col1.endswith('_x') and col2.endswith('_y'):
pairs.append((col1, col2))
for col1, col2 in pairs:
res[col1[:-2]] = res[col1].combine_first(res[col2])
res = res.drop([col1, col2], axis=1)
return res
print(reduce(my_merge, dfs))
输出:
A B C
a 1 4 7
b 2 5 8
c 3 6 9
不保留索引
这是一种方法:
from functools import reduce # Python 3 only
dfs = [df1, df2, df3, df3, df5]
def my_merge(df1, df2):
return pd.merge(df1, df2, how='outer')
merged_dfs = reduce(my_merge, dfs)
结果:
A B C
0 1 4 NaN
1 2 5 8
2 NaN 6 9
3 3 6 NaN
4 1 4 7
您可以通过设置方式
来调整连接方法:
how : {'left', 'right', 'outer', 'inner'}, default 'inner'
- left: use only keys from left frame (SQL: left outer join)
- right: use only keys from right frame (SQL: right outer join)
- outer: use union of keys from both frames (SQL: full outer join)
- inner: use intersection of keys from both frames (SQL: inner join)
如果您喜欢 lambda
,请使用此版本以获得相同的结果:
reduce(lambda df1, df2: pd.merge(df1, df2, how='outer'), dfs)
关于python - pandas:合并多个数据框,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34411495/