我对编码和Python非常陌生,我认为我咬得太多了,但我正在尝试创建一个程序,该程序读取包含3列信息的txt文件,然后获取这些列并列出它们。 然后,我想创建一个条件,将第三列行值与自身上方和下方的行进行比较,如果该值的差异大于 5,它将复制在第 3 列中找到该值的第 1 列和第 2 行,并且将其附加到一个名为“spikes”的新列表中,我希望可以用它创建一个新的单独的 txt 文件。 我的名称为“xyz_test.txt”的 txt 文件值示例:
98015.985 -4922343.462 101.098
98015.985 -4922343.712 101.098
98015.985 -4922343.962 101.093
98015.985 -4922344.212 101.089
98015.985 -4922344.462 108.09
98015.985 -4922344.712 101.095
98015.985 -4922344.962 101.093
98015.985 -4922345.212 101.083
98015.985 -4922345.462 101.081
到目前为止我能得到并弄清楚的内容如下:
import csv,math listxy = [] listz = [] spikes = [] files =
list(csv.reader(open('xyz_test.txt', 'rb'), delimiter='\t'))
for z in files:
listxy = z[0],z[1]
listz = z[2]
print listz
我得到的结果如下:
101.098
101.098
101.093
101.089
108.09
101.095
101.093
101.083
101.081
现在我尝试运行一个条件,首先找到列表中的一个数字,其差异大于其上方和下方的数字 5,但不断收到以下错误:
“并非所有参数在字符串格式化期间都被转换”
“无法连接‘str’和‘int’对象”
任何人都可以帮我解决这个问题吗?
Thanks for all the help from everyone, learned allot. i have changed the code to fit what i need , here is what i ended up with. still tweaking , have to create something that sorts the values and loop through several txt files but this is what have so far:
from __future__ import print_function
import pandas as pd
# sets dipslay to larger extent
#pd.set_option('display.height', 10000000)
#pd.set_option('display.max_rows', 5000000)
#pd.set_option('display.max_columns', 50)
#pd.set_option('display.width', 10000)
limit = 3
tries = 0
while True:
print ("----------------------------------------------------")
spikewell = float(raw_input("Please Enter Parameters: "))
tries += 1
if tries == 4:
print ("----------------------------------------------------")
print ("Entered incorrectly to many times.....Exiting")
print ("----------------------------------------------------")
break
else:
if spikewell > 50:
print ("parameters past limit (20)")
print ("----------------------------------------------------")
print (tries)
continue
elif spikewell < 0:
print ("Parameters cant be negative")
print ("----------------------------------------------------")
print (tries)
continue
else:
spikewell
print ("Parameters are set")
print (spikewell)
print ("Searching files")
print ("----------------------------------------------------")
terrain = "1_tile_test.txt"
for df in terrain:
df = pd.read_csv('1_tile_test.txt', sep=r'\s+', names=['____x____ ','____y____ ','____z____'])
# print orginal data frame (for testing)
# get spikes's coordinates
# df['col3'].shift(1) - previous value of the 'col3' column
# df['col3'].shift(-1) - next value of the 'col3' column
spikes = df.loc[(df['____z____'] - df['____z____'].shift(1) > spikewell) & \
(df['____z____'] - df['____z____'].shift(-1) > spikewell)]
wells = df.loc[-((df['____z____'] - df['____z____'].shift(1) > spikewell)) & \
-((df['____z____'] - df['____z____'].shift(-1)) > -spikewell)]
# print and save spikes
# print(spikes[['col1', 'col2','col3']])
# print(spikes2[['col1', 'col2','col3']])
# print(wells[['col1', 'col2','col3']])
# print(wells2[['col1', 'col2','col3']])
spikes[['____x____ ','____y____ ','____z____']].to_csv('spikes.txt', sep='\t', index=False)
#spikes2[['____x____ ','____y____ ','____z____']].to_csv('spikes.txt', sep='\t', index=False)
wells[['____x____ ','____y____ ','____z____']].to_csv('wells.txt', sep='\t', index=False)
#wells2[['____x____ ','____y____ ','____z____']].to_csv('wells.txt', sep='\t', index=False)
print ("----------------------------------------------------")
print ('Search completed')
break
break
最佳答案
这是一个例子:
import csv
def is_spike(three):
first, second, third = three
return abs(float(first[2]) - float(second[2])) > 5 and abs(float(second[2]) - float(third[2])) > 5
with open("yourcsvfile.csv") as csvfile:
reader = csv.reader(csvfile)
rows = list(reader)
threes = zip(rows, rows[1:], rows[2:])
spikes = [three for three in threes if is_spike(three)]
print spikes
输出(中间行是“尖峰”):
[(['98015.985', '-4922344.212', '101.089'], ['98015.985', '-4922344.462', '108.09'], ['98015.985', '-4922344.712', '101.095'])]
演练:
首先,我们使用 csv 模块读取整行数据,该模块为我们拆分数据。确保正确设置分隔符。您也可以手动阅读它们,但这更通用。
其次,我们压缩所有三个
(如三行),并使用相当简单的is_spike
函数检查它们是否形成“尖峰”。
祝你好运。
关于python - 打开包含 3 列的 txt 文件,条件是检查第三列是否有 5 的差异,并将该行的第 1 列和第 2 列返回到新的 txt 文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35722689/