我有一张球员与比赛的关系表以及他们在每场比赛中的得分。我正在尝试做一个 SELECT,在其中我得到一个不同的球员列表,他们的总得分以及他们所参加的所有球队的总得分。由于一切都是关于单人游戏,我不知道如何仅针对该单列退出 GROUP BY 范围。对于下面的例子,我只说每支球队只有两名球员。在实际数据库中,如果重要的话,每个团队都有五个。谢谢大家。
表格“匹配”:
match_id | winning_team |
56427859 | 0 |
56427860 | 1 |
56427861 | 1 |
56427862 | 0 |
56427863 | 1 |
etc...
表“match_players”:
match_id | team | player_id | points |
56427859 | 0 | 10 | 3 |
56427859 | 0 | 33 | 1 |
56427859 | 1 | 26 | 0 |
56427859 | 1 | 39 | 2 |
56427860 | 0 | 23 | 1 |
56427860 | 0 | 33 | 3 |
56427860 | 1 | 18 | 1 |
56427860 | 1 | 10 | 4 |
etc...
期望的结果:
player_id | match_count | total_points | team_total_points | <- This should be
the total of all
10 | 2 | 7 | 9 | points scored by
18 | 1 | 1 | 5 | the player and
23 | 1 | 1 | 4 | his teammates
26 | 1 | 0 | 2 | in all matches.
33 | 2 | 4 | 8 |
39 | 1 | 2 | 2 |
查询:
SELECT
p.player_id,
COUNT(*) AS match_count,
SUM(CASE WHEN mp.team = m.winning_team THEN 1 ELSE 0 END) AS win_count,
SUM(points) AS total_points,
[________________________________________] AS team_total_points
FROM matches m
INNER JOIN match_players mp ON m.match_id = mp.match_id
INNER JOIN players p ON mp.player_id = p.player_id
GROUP BY player_id
ORDER BY player_id
编辑:
“球队”一栏简单地定义了红色或蓝色、主场或客场等。球员可以在不同的比赛中属于不同的球队。玩家可以在比赛之间交换队伍,例如休息躲避球。
最佳答案
以下查询将计算与每个玩家同队的所有玩家的总分。
SELECT p1.player_id, SUM(p2.total_points) AS team_total_points
FROM match_players AS p1
JOIN (SELECT match_id, team, SUM(points) as total_points
FROM match_players
GROUP BY match_id, team) AS p2
ON p1.match_id = p2.match_id AND p1.team = p2.team
GROUP BY p1.player_id
然后您可以将其与原始查询结合起来以添加团队总数。
SELECT
p.player_id,
COUNT(*) AS match_count,
SUM(CASE WHEN mp.team = m.winning_team THEN 1 ELSE 0 END) AS win_count,
SUM(points) AS total_points,
mp2.team_total_points
FROM matches m
INNER JOIN match_players mp ON m.match_id = mp.match_id
INNER JOIN players p ON mp.player_id = p.player_id
INNER JOIN
(SELECT p1.player_id, SUM(p2.total_points) AS team_total_points
FROM match_players AS p1
JOIN (SELECT match_id, team, SUM(points) as total_points
FROM match_players
GROUP BY match_id, team) AS p2
ON p1.match_id = p2.match_id AND p1.team = p2.team
GROUP BY p1.player_id) AS mp2 ON mp2.player_id = p.player_id
GROUP BY player_id
ORDER BY player_id
关于mysql - 如何选择多个 GROUP BY 行的 SUM?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36808807/