python - 使用 LineProfiler 对 Django 应用程序进行逐行分析

Question

我想使用 line profiler 来分析我的 django 项目以显示代码性能的分析。

我正在关注这些链接:

1. http://djangotricks.blogspot.in/2015/01/performance-bottlenecks-in-django-views.html

2. https://github.com/dcramer/django-devserver

但这对我不起作用。我收到有关开发服务器的错误，如下所示:

Traceback (most recent call last):
  File "manage.py", line 10, in <module>
    execute_from_command_line(sys.argv)
  File "/.virtualenvs/test/lib/python3.4/site-packages/django/core/management/__init__.py", line 350, in execute_from_command_line
    utility.execute()
  File "/.virtualenvs/test/lib/python3.4/site-packages/django/core/management/__init__.py", line 342, in execute
    self.fetch_command(subcommand).run_from_argv(self.argv)
  File "/.virtualenvs/test/lib/python3.4/site-packages/django/core/management/__init__.py", line 195, in fetch_command
    klass = load_command_class(app_name, subcommand)
  File "/.virtualenvs/test/lib/python3.4/site-packages/django/core/management/__init__.py", line 39, in load_command_class
    module = import_module('%s.management.commands.%s' % (app_name, name))
  File "/.virtualenvs/test/lib64/python3.4/importlib/__init__.py", line 109, in import_module
    return _bootstrap._gcd_import(name[level:], package, level)
  File "<frozen importlib._bootstrap>", line 2254, in _gcd_import
  File "<frozen importlib._bootstrap>", line 2237, in _find_and_load
  File "<frozen importlib._bootstrap>", line 2226, in _find_and_load_unlocked
  File "<frozen importlib._bootstrap>", line 1200, in _load_unlocked
  File "<frozen importlib._bootstrap>", line 1129, in _exec
  File "<frozen importlib._bootstrap>", line 1467, in exec_module
  File "<frozen importlib._bootstrap>", line 1572, in get_code
  File "<frozen importlib._bootstrap>", line 1532, in source_to_code
  File "<frozen importlib._bootstrap>", line 321, in _call_with_frames_removed
  File "/.virtualenvs/test/lib/python3.4/site-packages/devserver/management/commands/runserver.py", line 29
    raise exc_type, exc_value, tb
                  ^
SyntaxError: invalid syntax

注意:我使用的版本 - Django:1.9 和 python:3.4

Answer 1

此处找到解决方案:https://lothiraldan.github.io/2018-02-18-python-line-profiler-without-magic/

在 Python 3.8 和 Django 3.2 上测试。

在 django 代码中的函数之前，粘贴以下内容:

import line_profiler
import atexit
profile = line_profiler.LineProfiler()
atexit.register(profile.print_stats)

@profile
def my_function_in_django_code():
    ....

然后，启动普通服务器./manage.py runserver。

当您退出服务器(Ctrl+C)时，退出时将显示 Line_profiler 的结果。

其他解决方案:简单地输出到文件:

import line_profiler
profile = line_profiler.LineProfiler()


@profile
def my_function_in_django_code():
    ....

    with open('output.txt', 'w') as stream:
        profile.print_stats(stream=stream)        

    return something