我有Python字典:
student_age = {'bala':20,'raju':21}
student_id = {'bala':289,'raju':567}
还有另外十个类似的字典,其键为学生姓名,值不同的字段。
而不是
worksheet.write(0,2,20)
我想根据学生姓名进行书写,例如 write("bala"-> "age",20)
更新的代码:
import xlsxwriter
workbook = xlsxwriter.Workbook('student_data.xlsx')
worksheet = workbook.add_worksheet()
student_age={'bala':20,'raju':21,'ram':22}
student_id={'bala':289,'ram':567,'raju':654}
students = student_id.keys()
print(len(student_age.keys()))
fields = [student_age, student_id] # add other dicts here...
for row, student in enumerate(students):
worksheet.write(row, 0, student) # name column
for col, student_data in enumerate(fields):
col = col + 1
worksheet.write(row, col, student_data[student])
workbook.close()
上面的代码工作正常,但存在以下争议:
- 输出从第 0 行第 0 列开始,但我想要第 1 行的标题并需要第 1 行的输出
- 如果student_id键是20,并且我有一本只有15个学生的字典,如何将这些项目留空而不出错并遍历它?
最佳答案
您可以简单地将所有 Python 字典添加到一个列表中,这样您就可以为每个学生迭代它们,以填充每一行的每一列。像这样的事情:
已更新以解决 OP 的评论
对于#1,只需将标题写入第一行,然后将其他行偏移一个
对于#2,您可以简单地利用 dict.get()
如果 id 不在该字典中,则使用 []
表示法来分配默认值:
import xlsxwriter
workbook = xlsxwriter.Workbook('student_data.xlsx')
worksheet = workbook.add_worksheet()
bold = workbook.add_format({'bold': 1})
students = student_id.keys()
fields = [student_age, student_id] # add other dicts here...
headers = ['name', 'age', 'id'] # ...
# write out a header row
for i, header in enumerate(headers):
worksheet.write(0, i, header, bold)
for row, student in enumerate(student):
row = row + 1
worksheet.write(row, 0, student) # name column
for col, student_data in enumerate(fields):
col = col + 1
worksheet.write(row, col, student_data.get(student, ''))
关于python xlsxwriter根据行数据写入单元格,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38117610/