python - 计算合并字符串的分数

Question

我试图弄清楚如何计算两个合并的姓名列表的分数。我需要为每个字符(包括名字和姓氏之间的空格)打一分，并为名字中的每个元音打一分。

a = ["John", "Kate", "Oli"]
b = ["Green", "Fletcher", "Nelson"]

vowel = ["a", "e", "i", "o", "u"]

gen = ((x, y) for x in a for y in b)

for u, v in gen:
    print u, v

我正在努力弄清楚该怎么做。任何帮助将不胜感激。

Answer 1

因此，您首先zip名字和姓氏，然后使用' '作为分隔符str。然后用collections.Counter计算所谓的元音字符出现的次数，将它们求和，并添加全名的len。这将是 dict 对象，然后你可以用它做任何你喜欢的事情。

from collections import Counter

a = ["John", "Kate", "Oli"]
b = ["Green", "Fletcher", "Nelson"]    
vowel = ["a", "e", "i", "o", "u"]

output = {}
for item in [' '.join(i) for i in zip(a,b)]:
    output[item] = sum(Counter(item)[x] for x in vowel) + len(item)
output

输出:

{'John Green': 13, 'Kate Fletcher': 17, 'Oli Nelson': 13}

更新

如果您需要名字和姓氏的所有可能变体，您可以使用 itertools.product 来实现。

from itertools import product
from collections import Counter

a = ["John", "Kate", "Oli"]
b = ["Green", "Fletcher", "Nelson"]    
vowel = ["a", "e", "i", "o", "u"]

output = {}
for item in [' '.join(i) for i in product(a,b)]:
    output[item] = sum(Counter(item)[x] for x in vowel) + len(item)
output

输出:

{'John Fletcher': 16,
 'John Green': 13,
 'John Nelson': 14,
 'Kate Fletcher': 17,
 'Kate Green': 14,
 'Kate Nelson': 15,
 'Oli Fletcher': 15,
 'Oli Green': 12,
 'Oli Nelson': 13}