我想提取 bookingId 为空的记录,并获得最大未预订天数(从第一个免费日算起)。预期结果应该是:
id = 1, 2013-08-03, 7 days free
id = 1, 2013-08-24, 7 days free
id = 2, 2013-08-07, 10 days free
id = 2, 2013-08-24, 7 days free
最好的办法是,如果我还可以查询空闲时间段:例如查询 1、2、3、4、5、6、7..14.. 空闲天数。这是我的源数据的示例:
id bookingDate bookingId
--------------------------------
1 2013-08-03 0
1 2013-08-04 0
1 2013-08-05 0
1 2013-08-06 0
1 2013-08-07 0
1 2013-08-08 0
1 2013-08-09 0
1 2013-08-10 112
1 2013-08-11 112
1 2013-08-12 112
1 2013-08-13 112
1 2013-08-14 112
1 2013-08-15 112
1 2013-08-16 112
1 2013-08-17 112
1 2013-08-18 112
1 2013-08-19 112
1 2013-08-20 112
1 2013-08-21 112
1 2013-08-22 112
1 2013-08-23 112
1 2013-08-24 0
1 2013-08-25 0
1 2013-08-26 0
1 2013-08-27 0
1 2013-08-28 0
1 2013-08-29 0
1 2013-08-30 0
1 2013-08-31 0
2 2013-08-03 78
2 2013-08-04 78
2 2013-08-05 78
2 2013-08-06 78
2 2013-08-07 0
2 2013-08-08 0
2 2013-08-09 0
2 2013-08-10 0
2 2013-08-11 0
2 2013-08-12 0
2 2013-08-13 0
2 2013-08-14 0
2 2013-08-15 0
2 2013-08-16 0
2 2013-08-17 39
2 2013-08-18 39
2 2013-08-19 39
2 2013-08-20 39
2 2013-08-21 39
2 2013-08-22 39
2 2013-08-23 39
2 2013-08-24 0
2 2013-08-25 0
2 2013-08-26 0
2 2013-08-27 0
2 2013-08-28 0
2 2013-08-29 0
2 2013-08-30 0
2 2013-08-31 0
如果有人有更好的数据结构的好主意,我可以尝试实现。数据库仍在 build 中:-)
编辑:
CREATE TABLE IF NOT EXISTS `pricesBookings` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`baseId` int(11) NOT NULL,
`bookingDate` date NOT NULL,
`bookingId` int(11) NOT NULL,
`price` decimal(10,2) NOT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `baseId` (`baseId`,`bookingDate`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
最佳答案
这应该给出正确的结果:
select
id,
min(startDate) as startFreeDate,
count(*) - (endDate is null) numFreeDays
from (
select
pb1.id,
pb1.bookingDate startDate,
min(pb2.bookingDate) endDate
from
pricesBookings pb1 left join pricesBookings pb2
on pb1.id=pb2.id
and pb2.price>0
and pb2.bookingDate>pb1.bookingDate
where
pb1.price=0
group by
pb1.id,
pb1.bookingDate
) s
group by id, endDate
order by id, startDate
查看here .
如果需要搜索所有空闲时段,比如14天,可以加上HAVING:
group by id, endDate
having count(*) - (endDate is null) >= 14
order by id, startDate
关于mysql - 使用 mysql 查找日期间隔,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14731343/