我正在学习 Python 中的 Beautiful Soup 和字典。我正在关注斯坦福大学的 Beautiful Soup 简短教程，可以在这里找到:http://web.stanford.edu/~zlotnick/TextAsData/Web_Scraping_with_Beautiful_Soup.html
由于禁止访问网页，我已将教程中提供的文本存储为字符串，然后将字符串 soup 转换为 soup 对象。打印输出如下:
print(soup_string)
<html><body><div class="ec_statements"><div id="legalert_title"><a
href="/Legislation-and-Politics/Legislative-Alerts/Letter-to-Senators-
Urging-Them-to-Support-Cloture-and-Final-Passage-of-the-Paycheck-
Fairness-Act-S.2199">'Letter to Senators Urging Them to Support Cloture
and Final Passage of the Paycheck Fairness Act (S.2199)
</a>
</div>
<div id="legalert_date">
September 10, 2014
</div>
</div>
<div class="ec_statements">
<div id="legalert_title">
<a href="/Legislation-and-Politics/Legislative-Alerts/Letter-to-
Representatives-Urging-Them-to-Vote-on-the-Highway-Trust-Fund-Bill">
Letter to Representatives Urging Them to Vote on the Highway Trust Fund Bill
</a>
</div>
<div id="legalert_date">
July 30, 2014
</div>
</div>
<div class="ec_statements">
<div id="legalert_title">
<a href="/Legislation-and-Politics/Legislative-Alerts/Letter-to-Representatives-Urging-Them-to-Vote-No-on-the-Legislation-Providing-Supplemental-Appropriations-for-the-Fiscal-Year-Ending-Sept.-30-2014">
Letter to Representatives Urging Them to Vote No on the Legislation Providing Supplemental Appropriations for the Fiscal Year Ending Sept. 30, 2014
</a>
</div>
<div id="legalert_date">
July 30, 2014
</div>
</div>
</body></html>
在某些时候，导师会捕获 soup 对象中具有标签“div”、class_="ec_statements"的所有元素。
letters = soup_string.find_all("div", class_="ec_statements")
然后导师说:
“我们将遍历信件集合中的所有项目，对于每一项，提取名称并将其作为我们字典中的键。该值将是另一个字典，但我们尚未找到其他项目的内容，因此我们只需创建分配一个空的 dict 对象。”
此时，我采取了不同的方法，我决定首先将数据存储在列表中，然后存储在数据框中。代码如下:
lobbying_1 = []
lobbying_2 = []
lobbying_3 = []
for element in letters:
lobbying_1.append(element.a.get_text())
lobbying_2.append(element.a.attrs.get('href'))
lobbying_3.append(element.find(id="legalert_date").get_text())
df =pd.DataFrame([])
df = pd.DataFrame(lobbying_1, columns = ['Name'] )
df['href'] = lobbying_2
df['Date'] = lobbying_3
输出如下:
print(df)
Name \
0 \n 'Letter to Senators Urging Them to S...
1 \n Letter to Representatives Urging Th...
2 \n Letter to Representatives Urging Th...
href \
0 /Legislation-and-Politics/Legislative-Alerts/L...
1 /Legislation-and-Politics/Legislative-Alerts/L...
2 /Legislation-and-Politics/Legislative-Alerts/L...
Date
0 \n September 10, 2014\n
1 \n July 30, 2014\n
2 \n July 30, 2014\n
我的问题是:有没有办法通过 Beautiful Soup 获得更干净的数据，即没有\n 和空格的字符串，而只是真正的值？或者我必须使用正则表达式对数据进行后处理？
我们将不胜感激您的建议。
最佳答案
要删除文本中的换行符，请在调用 get_text() 时传递 strip=True:
for element in letters:
lobbying_1.append(element.a.get_text(strip=True))
lobbying_2.append(element.a.attrs.get('href'))
lobbying_3.append(element.find(id="legalert_date").get_text(strip=True))
当然，这是假设您仍然希望数据采用 DataFrame 的形式。
关于python - 获取干净数据: Beautiful Soup is enough or I must use Regex as well?，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/41554113/