python - 使用 Bokeh 绘制具有不同半径(不同大小)和基于值的不同颜色的纬度/经度点

Question

我有一个代码可以生成美国 map ，其中的点位于指定的经纬度坐标处。每个点都标记有一个值，我想用该值来指示该点应该有多大以及该点应该是什么颜色。代码如下:

points = pd.read_csv(f)
lat = []
lon = []
heat = []
const = []

for i in range(points.shape[0]):
    lat.append(points.iat[i,0])
    lon.append(points.iat[i,1])
    heat.append(points.iat[i,2])
    const.append(points.iat[i,3])

source = ColumnDataSource(
    data = dict(
        lat = lat,
        lon = lon,
        radius = heat,
        constr = const,
        )
    )
TOOLS = 'box_zoom,wheel_zoom,hover'
state_xs = [states[code]["lons"] for code in states]
state_ys = [states[code]["lats"] for code in states]
p = figure(title="Bound Portfolio", toolbar_location="left",
       plot_width=1100, plot_height=700, tools = TOOLS)
p.patches(state_xs, state_ys, fill_alpha=0.3, fill_color = "orange",
      line_color="#884444", line_width=2, line_alpha=0.3)
circle = Circle(x="lon", y="lat", size=4.5, fill_color="blue", fill_alpha=0.5, line_color=None)
#circle = Circle(x="lon", y="lat", size=4.5, fill_color="blue", fill_alpha=0.5, line_color=None)
p.add_glyph(source, circle)

lat、lon、heat 和 const 是我通过读取 pandas 数据帧的行创建的列表。我希望热值 (1-10) 是相关点的半径。我希望 const 中的每个唯一值映射到相关点的唯一颜色。我一直无法弄清楚如何使这段代码工作。我尝试过对圆圈的大小进行多种变化，但没有成功……颜色也是如此。

Answer 1

这是一个具有独特 Alpha、颜色和大小的示例。 关键是将值存储在列数据源中，然后将其作为参数传递到图形方法中 - 即 .circle("xname", "yname", source=source)

from bokeh.io import show
from bokeh.plotting import figure, ColumnDataSource

lat = [0,1,2,3]
lon = [10,20,30,40]
radius = [1,2,3,4]
constr = [100,200,300,400]
colors= ['#014636', '#016c59','#02818a', '#3690c0']
alpha=[0.8,0.1,0.3,0.5]

source = ColumnDataSource(
    data = dict(
        lat = lat,
        lon = lon,
        radius = radius,
        constr = constr,
        colors=colors,
        alpha=alpha
        )
    )

p = figure(title="Bound Portfolio",
       plot_width=1100, plot_height=700)
p.circle("lon","lat",source=source, fill_alpha="alpha", fill_color = "colors",
      line_color="colors", line_width=2, line_alpha=0.3,radius="radius")