Python 骰子结果计数

Question

编写一个函数collect_sims(nsim,N,D,p=0.5,nmax=10000)，它运行run_sim函数nsim次(参数为N、D、p)并返回一个长度为nmax的numpy数组，给出的数量模拟执行指定步数后停止的次数。例如，假设 nsim 为 8，连续运行 run_sim 会得到 3,4,4,3,6,5,4,4。您可以将其制表为“两个 3、四个 4、一个 5、一个 6、零个 7、零个 8……”

def collect_sims(nsim, N, D, p=0.5, nmax=10000):
    run_sim(N=20, D=6, p=0.5, itmax=5000)
    onecount = 0
    twocount = 0
    threecount = 0
    fourcount = 0
    fivecount = 0
    sixcount = 0
    for k in range (n):
        if D == 1:
            onecount += 1
        if D == 2:
            twocount += 1
        if D == 3:
            threecount += 1
        if D == 4:
            fourcount += 1
        if D == 5:
            fivecount += 1
        if D == 6:
            sixcount += 1

return(k)

print(onecount, "1",twocount,"2",threecount,"3",fourcount,"4",fivecount,"5",sixcount,"6")

它说我的 6 个变量 onecount、twocount 等未定义，我该如何定义它们？另外，我可以做什么来修复我的代码？

Answer 1

我不知道你为什么要返回 k。

无论如何，问题是 oncount、twocount 等位于不同的打印范围内。您可以将 print() 放在函数内，也可以返回包含计数的元组

有些是这样的:

def collect_sims(nsim, N, D, p=0.5, nmax=10000):
    run_sim(N=20, D=6, p=0.5, itmax=5000)
    onecount = 0
    twocount = 0
    threecount = 0
    fourcount = 0
    fivecount = 0
    sixcount = 0
for k in range (n):
    if D == 1:
       onecount += 1
    if D == 2:
       twocount += 1
    if D == 3:
       threecount += 1
    if D == 4:
       fourcount += 1
    if D == 5:
       fivecount += 1
    if D == 6:
       sixcount += 1

return(onecount, twocount, threecount, fourcount,fivecount,sixcount)

onecount, twocount, threecount, fourcount,fivecount,sixcount = collect_sims (...)

print(onecount, "1",twocount,"2",threecount,"3",fourcount,"4",fivecount,"5",sixcount,"6")

不同的解决方案

也许这个其他解决方案可以帮助您:

https://stackoverflow.com/a/9744274/6237334