python - Pyglet，播放完所有声音后退出

Question

AVbin 已安装。 .wav 和 .mp3 文件都可以使用。

import pyglet

music = pyglet.media.load('A.mp3')
music.play()

player = pyglet.media.Player()
player.queue( pyglet.media.load('B.mp3'))
player.queue( pyglet.media.load('C.wav'))

player.play()


pyglet.app.run()

pyglet.app.exit()

<小时/> 我想创建一个程序，播放 A，然后播放队列中的 B，然后播放 C，最后在播放完所有三个声音后退出。

我尝试了上面的代码，但根据 this帖子，“这[仅仅]因为 app.run() 是一个永无休止的循环。”

<小时/>

如何最少地修改我的代码，以便程序在播放三个声音后退出？

奖励，但是我如何才能最小程度地修改我的代码，以便程序可以播放两个(或更多)声音文件，E.mp3 和 F.mp3，位于一次？

谢谢!

Answer 1

因为你问的问题并不像你想象的那么简单。
我已经将一个代码示例与尽可能多的注释放在一起，而不会使示例难以阅读。

在代码下面，我将尝试尽可能详细地解释几个关键函数。

import pyglet
from pyglet.gl import *
from collections import OrderedDict

key = pyglet.window.key

class main(pyglet.window.Window):
    def __init__ (self, width=800, height=600, fps=False, *args, **kwargs):
        super(main, self).__init__(width, height, *args, **kwargs)

        self.keys = OrderedDict() # This just keeps track of which keys we're holding down. In case we want to do repeated input.
        self.alive = 1 # And as long as this is True, we'll keep on rendering.

        ## Add more songs to the list, either here, via input() from the console or on_key_ress() function below.
        self.songs = ['A.wav', 'B.wav', 'C.wav']
        self.song_pool = None

        self.player = pyglet.media.Player()
        for song in self.songs:
            media = pyglet.media.load(song)
            if self.song_pool is None:
                ## == if the Song Pool hasn't been setup,
                ##    we'll set one up. Because we need to know the audio_format()
                ##    we can't really set it up in advance (consists more information than just 'mp3' or 'wav')
                self.song_pool = pyglet.media.SourceGroup(media.audio_format, None)
            ## == Queue the media into the song pool.
            self.song_pool.queue(pyglet.media.load(song))

        ## == And then, queue the song_pool into the player.
        ##    We do this because SourceGroup (song_pool) as a function called
        ##    .has_next() which we'll require later on.
        self.player.queue(self.song_pool)
        ## == Normally, you would do self.player.eos_action = self.function()
        ##    But for whatever windows reasons, this doesn't work for me in testing.
        ##    So below is a manual workaround that works about as good.

        self.current_track = pyglet.text.Label('', x=width/2, y=height/2+50, anchor_x='center', anchor_y='center')
        self.current_time = pyglet.text.Label('', x=width/2, y=height/2-50, anchor_x='center', anchor_y='center')


    def on_draw(self):
        self.render()

    def on_close(self):
        self.alive = 0

    def on_key_release(self, symbol, modifiers):
        try:
            del self.keys[symbol]
        except:
            pass

    def on_key_press(self, symbol, modifiers):
        if symbol == key.ESCAPE: # [ESC]
            self.alive = 0

        elif symbol == key.SPACE:
            if self.player.playing:
                self.player.pause()
            else:
                self.player.play()

        elif symbol == key.RIGHT:
            self.player.seek(self.player.time + 15)

        ## == You could check the user input here,
        ##    and add more songs via the keyboard here.
        ##    For as long as self.song_pool has tracks,
        ##    this player will continue to play.

        self.keys[symbol] = True

    def end_of_tracks(self, *args, **kwargs):
        self.alive=0

    def render(self):
        ## Clear the screen
        self.clear()
        
        ## == You could show some video, image or text here while the music plays.
        ##    I'll drop in a example where the current Track Name and time are playing.

        ## == Grab the media_info (if any, otherwise this returns None)
        media_info = self.player.source.info
        if not media_info:
            ## == if there were no meta-data, we'll show the file-name instead:
            media_info = self.player.source._file.name
        else:
            ## == But if we got meta data, we'll show "Artist - Track Title"
            media_info = media_info.author + ' - ' + media_info.title

        self.current_track.text = media_info
        self.current_track.draw()

        ## == This part exists of two things,
        ## 1. Grab the Current Time Stamp and the Song Duration.
        ##    Check if the song_pool() is at it's end, and if the track Cur>=Max -> We'll quit.
        ## *  (This is the manual workaround)
        cur_t, end_t = int(self.player.time), int(self.player.source._get_duration())
        if self.song_pool.has_next() is False and cur_t >= end_t:
            self.alive=False

        ## 2. Show the current time and maximum time in seconds to the user.
        self.current_time.text = str(cur_t)+'/'+str(end_t) + 'seconds'
        self.current_time.draw()

        ## This "renders" the graphics:
        self.flip()

    def run(self):
        while self.alive == 1:
            self.render()

            # -----------> This is key <----------
            # This is what replaces pyglet.app.run()
            # but is required for the GUI to not freeze
            #
            event = self.dispatch_events()

x = main()
x.run()

现在，通常您会用一堆函数来装饰您的方式。 但我喜欢通过任何图形库进行子类化和面向对象编程，因为否则它会很快变得困惑。

因此，我有一个自定义的 run() 函数，而不是 pyglet.app.run()。
大多数情况下，这一切都是模仿 pyglet.app.run() 。至少足以开始。

因为 player.eos_* 事件似乎已损坏。
我添加了一个手动示例，说明如何检查歌曲是否播放完毕。

这是self.song_pool pyglet.media.SourceGroup的组合, self.player.time pyglet.media.player.time和 self.player.source._get_duration() 返回轨道持续时间。

SourceGroup 为我们提供了一个 has_next() 函数，该函数告诉我们是否处于排队歌曲的末尾。另外两个变量告诉我们是否已经到达当前轨道的末尾。这就是我们需要确定是否要退出的全部内容。

现在，我还没有从技术上添加添加更多歌曲的方法。因为这又比你想象的要困难。除非您选择使用 if symbol == key.LCTRL: self.song_pool.queue(pyglet.media.load(input('Song: '))) 例如。但同样，您需要做的就是将更多歌曲添加到 self.song_pool 队列中，然后就可以了。

我希望这能回答您的问题。甚至还有奖金。