python - 在python中提取不匹配的字符串

Question

我有两个字符串 s 和 s2

s = "catwalksonterrace9_ontheweekend_at7am"
s2= "catwalksonterrace$no_ontheweekend_at.*"

我需要比较两个字符串并提取不匹配的部分 $no = 9 和 .* = 7am 来自 Python 中的两个字符串。我是 python 新手，我该如何实现这一目标？

Answer 1

看看 difflib，它太棒了，完全可以做你想做的事:) https://docs.python.org/2/library/difflib.html

import difflib
d = difflib.Differ()
diffs = []
in_diff = False
for c in d.compare(s, s2):
    if not in_diff and (c.startswith("+") or c.startswith("-")):
        diffs.append(["", ""])
        in_diff = True
    if c.startswith("+"):
        diffs[-1][0] += c.replace("+ ", "")
    elif c.startswith("-"):
        diffs[-1][1] += c.replace("- ", "")
    else:
        in_diff = False
print(diffs)

这会创建一个列表列表，其中每个子列表的第一个值是第 1 行的 diff，第二个值是第 2 行的 diff

输出将是:

[['$no', '9'], ['.*', '7am']]

然后您可以循环遍历它，按要求打印出来:

for diff in diffs:
    print(diff[0], "=", diff[1])