python - 从类中返回 subprocess.Popen 的输出

Question

我正在尝试实现一个多线程类，并希望使用输出来确定程序中下一步要做什么。如何将 self.process 的输出作为字符串返回？如果我尝试返回 self.process.communicate 的输出，则会收到错误。

#class for multi threading
class Command(object):
    def __init__(self,cmd):
        self.cmd = cmd
        self.process = None

    def run(self,timeout):
        def target():
            print("Thread started")
            self.process = subprocess.Popen(self.cmd,stdout=subprocess.PIPE)
            self.process.communicate()                        
            print("Thread finished")            

        thread = threading.Thread(target=target)
        thread.start()

        thread.join(timeout)
        if thread.is_alive():
            print("\nTerminating process")
            self.process.terminate()
            thread.join()            
        print(self.process.returncode) 

def unzip_file(zipped):    
    command = Command(zip_exe+' x '+zipped)
    command.run(timeout = 12000)

unzip_file(zipped) 

Answer 1

这通常是我获取进程输出的方法:

class SExec:

def __init__(self, _command):

    _process = Popen(_command, shell=True, stdout=PIPE, stderr=STDOUT, close_fds=True)

    if _process.stderr is None:
        self.stdout = (_process.stdout.read()).decode("utf-8")
        self.return_code = _process.returncode
    else:
        self.stdout = None
        self.stderr = _process.stderr.decode("utf-8")

然后，举个例子，当我想要执行某些操作并获得它的返回时，我可以这样做:

    dir_info = SExec('ls -lA').stdout
    for _line in dir_info.split('\n'):
        print(_line)

希望我的例子对你有帮助。问候。