python - 如何打印列表的某些部分？

Question

这是我的代码:

def option_A():
 print("Pick a Fixture!")
 fixture_choice = int(input("Enter: "))

 file = open("firesideFixtures.txt", "r")
 fixture_number = file.readlines(fixture_choice)
 fixture = [linecache.getline("firesideFixtures.txt", fixture_choice)] 
 print(fixture)
 file.close()

我正在使用的文件的第一行是:

1,02/09/15,18:00,RNGesus,Ingsoc,Y,Ingsoc

预期结果是:

1, 02/09/15, RNGesus, Ingsoc, Y, Ingsoc

我得到的结果:

['1,02/09/15,18:00,RNGesus,Ingsoc,Y,Ingsoc\n']

我该怎么做？

Answer 1

通过索引来打印列表中的唯一元素:

print(fixture[0])

输出:

1,02/09/15,18:00,RNGesus,Ingsoc,Y,Ingsoc

或者，最好不要首先创建列表(注意缺少的 []):

fixture = linecache.getline("firesideFixtures.txt", fixture_choice) 

How can I remove the "18:00" part from the output because all I need is "1,02/09/15, RNGesus, Ingsoc, Y, Ingsoc" (from comment)

现在，删除时间:

fixture = linecache.getline("firesideFixtures.txt", fixture_choice) 
parts = fixture.split(',')
res = ','.join(parts[:2] + parts[3:])
print(res)
print(fixture)

输出:

1,02/09/15,RNGesus,Ingsoc,Y,Ingsoc