我将数组 Amp 乘以另一个 B**w，其中 W 是另一个数组，然后对每个 w 的结果数组求和。
Amp 和 B 的大小为 (4867206,1)，W 的大小为 (40x10^3,1)。
如果 W 的大小为 (1000,1)，当前需要 2 分 49 秒。当使用尺寸为 40x10^3 的完整 W 时，如何提高这个速度？
Hw2=[np.einsum('i,i->', Amp, (np.array(B)**w)) for w in W]
最佳答案
有两件事可以给你带来健康的加速:
1) 您不希望将 array 工厂放在列表组件中。实际上速度很慢。
2) 计算log(B)，然后使用exp而不是**。这节省了很多。
>>> Amp = np.random.random(4867206)
>>> B = np.random.random(4867206)
>>> W = 10 * np.random.random(40000) + 1
>>>
>>> from time import perf_counter
>>>
>>> t = perf_counter(); logB = np.log(B); s = perf_counter()
>>> s-t
0.1715415450744331
>>>
>>> t = perf_counter(); [np.einsum('i,i->', Amp, B**w) for w in W[:40]]; s = perf_counter()
[232552.87174648093, 307130.7390907966, 411262.86511309125, 361323.4099230686, 254219.3700454278, 291692.2455839877, 324589.6747811661, 762459.3664474463, 224831.38520298406, 501641.86340860004, 466934.72400738456, 441544.52557156974, 995259.4253344169, 207811.00874071234, 408355.53573396447, 269901.94895861426, 304678.5850806002, 208719.98547583033, 318300.7763362345, 271688.90632957884, 388056.3735974982, 362437.1587603325, 456415.8506358219, 567634.1566253774, 418715.1493866043, 698332.545166694, 711861.6705545874, 391412.016841215, 569291.0132128834, 331811.20195587486, 898976.2873925611, 230896.99034275368, 225609.32356150646, 220438.15228011008, 526091.9360881918, 388536.063436256, 297158.4095318841, 382482.6531720307, 234679.1485575674, 263925.33778147714]
>>> s-t
15.207583270967007
>>>
>>> t = perf_counter(); [np.einsum('i,i->', Amp, np.exp(w * logB)) for w in W[:40]]; s = perf_counter()
[232552.87174648093, 307130.7390907966, 411262.8651130912, 361323.4099230686, 254219.3700454278, 291692.2455839877, 324589.6747811661, 762459.3664474462, 224831.38520298406, 501641.86340860004, 466934.72400738456, 441544.52557156974, 995259.4253344169, 207811.00874071234, 408355.5357339644, 269901.9489586143, 304678.5850806002, 208719.98547583033, 318300.7763362345, 271688.90632957884, 388056.3735974982, 362437.1587603325, 456415.8506358219, 567634.1566253774, 418715.1493866043, 698332.545166694, 711861.6705545874, 391412.016841215, 569291.0132128834, 331811.20195587486, 898976.2873925611, 230896.99034275368, 225609.32356150646, 220438.15228011008, 526091.9360881918, 388536.063436256, 297158.4095318842, 382482.6531720308, 234679.1485575674, 263925.33778147714]
>>> s-t
5.111462005996145
关于python - 如何提高数组大小 9e3 的列表理解速度？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/49794144/