python显示矩阵除法后的剩余值

Question

i = [1,2,3,4,5,6,7,8,9,10]
def ndiv(l,n):
     return [l[s:e] for s, e in zip(range(0,len(l)+1,n),xrange(n,len(l)+1,n))]
for i in xrange(1,15,1):
    print "CLUSTER {}".format((ndiv(l,i)))

#print 
CLUSTER [[1], [2], [3], [4], [5], [6], [7], [8], [9], [10], [11], [12], [13], [14], [15], [16], [17]]
CLUSTER [[1, 2], [3, 4], [5, 6], [7, 8], [9, 10], [11, 12], [13, 14], [15, 16]]
CLUSTER [[1, 2, 3], [4, 5, 6], [7, 8, 9], [10, 11, 12], [13, 14, 15]]
CLUSTER [[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]]
CLUSTER [[1, 2, 3, 4, 5], [6, 7, 8, 9, 10], [11, 12, 13, 14, 15]]
CLUSTER [[1, 2, 3, 4, 5, 6], [7, 8, 9, 10, 11, 12]]
CLUSTER [[1, 2, 3, 4, 5, 6, 7], [8, 9, 10, 11, 12, 13, 14]]
CLUSTER [[1, 2, 3, 4, 5, 6, 7, 8], [9, 10, 11, 12, 13, 14, 15, 16]]
CLUSTER [[1, 2, 3, 4, 5, 6, 7, 8, 9]]

到目前为止正在编码。分割后，剩余的值不会被省略。但我想显示分割后的价格(例如，如果除 '3' ->before [[1, 2, 3, 4, 5], [6, 7, 8, 9, 10], [11, 12, 13, 14, 15]]/[[1, 2, 3, 4, 5], [6, 7, 8, 9, 10], [11] 之后, 12, 13, 14, 15],[16],[17] ).如何除掉然后一一显示剩余的数字？

Answer 1

您可以计算 2 个列表，一个包含 n 个批处理的拆分列表，另一个将剩余元素映射到一个元素列表中，最后将它们合并在一起

>>> l = list(xrange(1,18))
>>> def ndiv(l,n):
...     return [l[i:i+n] for i in xrange(0,len(l)//n*n, n)] + [[e] for e in l[len(l)//n*n:]]
... 
>>> ndiv(l, 5)
[[1, 2, 3, 4, 5], [6, 7, 8, 9, 10], [11, 12, 13, 14, 15], [16], [17]]