我正在编写一个Python代码来从输入文件中提取所有URL，其中包含来自Twitter(推文)的内容或文本。然而，在这样做时，我意识到在 python 列表中提取的几个 URL 在末尾有“特殊字符”或“标点符号”，因此我无法进一步解析它们以获取基本 URL 链接。我的问题是:“如何识别并删除列表中每个网址末尾的特殊字符”？
当前输出:
['https://twitter.com/GVNyqWEu5u', 'https://twitter.com/GVNyqWEu5u'', 'https://twitter.com/GVNyqWEu5u@#', 'https://twitter.com/GVNyqWEu5u"']
期望的输出:
['https://twitter.com/GVNyqWEu5u', 'https://twitter.com/GVNyqWEu5u', 'https://twitter.com/GVNyqWEu5u', 'https://twitter.com/GVNyqWEu5u']
您会发现，并非“当前输出”列表中的所有元素在末尾都有特殊字符/标点符号。任务是仅从具有字符/标点符号的列表元素中识别和删除它们。
我使用以下正则表达式从推文文本中提取 Twitter URL:lst = re.findall('(http.?://[^\s]+)', text)
我可以在此步骤中删除 URL 末尾的特殊字符/标点符号吗？
完整代码:
import urllib.request, urllib.parse, urllib.error
from bs4 import BeautifulSoup
from socket import timeout
import ssl
import re
import csv
ctx = ssl.create_default_context()
ctx.check_hostname = False
ctx.verify_mode = ssl.CERT_NONE
count = 0
file = "Test.CSV"
with open(file,'r', encoding='utf-8') as f, open('output_themes_1.csv', 'w', newline='', encoding='utf-8') as ofile:
next(f)
reader = csv.reader(f)
writer = csv.writer(ofile)
fir = 'S.No.', 'Article_Id', 'Validity', 'Content', 'Geography', 'URL'
writer.writerow(fir)
for line in reader:
count = count+1
text = line[5]
lst = re.findall('(http.?://[^\s]+)', text)
if not lst:
x = count, line[0], 'Empty List', text, line[8], line[6]
print (x)
writer.writerow(x)
else:
try:
for url in lst:
try:
html = urllib.request.urlopen(url, context=ctx, timeout=60).read()
#html = urllib.request.urlopen(urllib.parse.quote(url, errors='ignore'), context=ctx).read()
soup = BeautifulSoup(html, 'html.parser')
title = soup.title.string
str_title = str (title)
if 'Twitter' in str_title:
if len(lst) > 1: break
else: continue
else:
y = count, line[0], 'Parsed', str_title, line[8], url
print (y)
writer.writerow(y)
except UnicodeEncodeError as e:
b_url = url.encode('ascii', errors='ignore')
n_url = b_url.decode("utf-8")
try:
html = urllib.request.urlopen(n_url, context=ctx, timeout=90).read()
soup = BeautifulSoup(html, 'html.parser')
title = soup.title.string
str_title = str (title)
if 'Twitter' in str_title:
if len(lst) > 1: break
else: continue
else:
z = count, line[0], 'Parsed_2', str_title, line[8], url
print (z)
writer.writerow(z)
except Exception as e:
a = count, line[0], str(e), text, line[8], url
print (a)
writer.writerow(a)
except Exception as e:
b = count, line[0], str(e), text, line[8], url
print (b)
writer.writerow(b)
print ('Total Rows Analyzed:', count)
最佳答案
假设特殊字符出现在您可以使用的字符串末尾:
mydata = ['https://twitter.com/GVNyqWEu5u', "https://twitter.com/GVNyqWEu5u'", 'https://twitter.com/GVNyqWEu5u@#', 'https://twitter.com/GVNyqWEu5u"']
mydata = [re.sub('[^a-zA-Z0-9]+$','',item) for item in mydata]
print(mydata)
打印:
['https://twitter.com/GVNyqWEu5u', 'https://twitter.com/GVNyqWEu5u', 'https://twitter.com/GVNyqWEu5u', 'https://twitter.com/GVNyqWEu5u']
关于python - 删除 Python URL 列表末尾的特殊字符/标点符号，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/52118382/