Python - 输入用户输入的天数，然后显示等效的年、月和日

Question

我正在努力寻找针对日期部分的算法。不过，我可以把几年和几个月记下来。这是我的代码

def main():

    # Prompt the user for an integer that represents a total number of days 
    user_days = int(input("Enter a total number of days: "))

    # constant variables for: years, months, days

    DAYS_IN_YEAR = 365
    DAYS_IN_MONTH = 30

    # Calculate the user's days into equivalent years
    years = (int(user_days // DAYS_IN_YEAR))

    # Calculate the user's days into equivalent months
    months = (int(user_days // DAYS_IN_MONTH))

    # Calculate the user's days into equivalent days
    # days = (int( user_days - DAYS_IN_MONTH ))
    # days = (int( ))

    # give user their results
    print(user_days, "days are equivalent to: ")

    # display the equivalent years
    print("Years: ", years)

    # display the equivalent months
    print("Months: ", months)

    # display the equivalent days
    print("Days: ", days)



main()

Answer 1

首先，你用你的天做floor div除以365，得到你的年。然后我们需要剩余的天数，因此我们使用天数模 365 并获得剩余的天数，我们将这些天数floor div 除以30，以获得我们的月份。然后我们用原来的剩余天数和 modulus 30 来得到剩余的天数

days = int(input())
years = days // 365
years_r = days % 365
months = years_r // 30
days_r = years_r % 30

400
Years: 1, Months: 1, Days: 5
500
Years: 1, Months: 4, Days: 15