这里完全是初学者。以下代码旨在分析网站中的 p 标签(使用 Python)并显示网站的阅读级别。
#import both BS4 and the new URLLIB using the added .request
from urllib.request import urlopen as uReq
from bs4 import BeautifulSoup as soup
#credit to AbigailB (https://stackoverflow.com/users/1798848/abigailb)
def syllables(word):
count = 0
vowels = 'aeiouy'
word = word.lower().strip(".:;?!")
if word[0] in vowels:
count += 1
for index in range(1,len(word)):
if word[index] in vowels and word[index-1] not in vowels:
count += 1
if word.endswith('e'):
count -= 1
if word.endswith('le'):
count+=1
if count == 0:
count += 1
return count
#site prompt, to be replaced by active tab browser address
#site = input("Enter the website to find out its reading level:")
#my_url = "{}".format(site)
#default site for testing
my_url = "https://en.wikipedia.org/wiki/Jane_Austen"
uClient = uReq(my_url)
page_html = uClient.read()
uClient.close()
#empty variables to be pushed w/ extracted, looped text
senNum = []
wordNum = []
syllNum = []
page_soup = soup(page_html, "html.parser")
page_soup.findAll("p")
paragraphs = page_soup.findAll("p")
#loop through every paragraph, do magic
for para in paragraphs:
para = para.text.strip()
paraSen = int(len(para.split('.')) - 1)
paraWord = int(len(para.split()))
paraSyll = syllables(para)
intParaSen = int(paraSen)
intParaWord = int(paraWord)
intParaSyll = int(paraSyll)
#append stripped values into empty variables
senNum.append(intParaSen)
wordNum.append(intParaWord)
syllNum.append(intParaSyll)
#sums of all previously empty values
sumSenNum = sum(senNum)
sumWordNum = sum(wordNum)
sumSyllNum = sum(syllNum)
#averages for Flesch–Kincaid ease
avgWordsPerSen = sumWordNum/sumSenNum
avgSyllPerWord = sumSyllNum/sumWordNum
#final parts for Flesch–Kincaid ease
calcOne = avgWordsPerSen * 0.39
calcTwo = avgSyllPerWord * 11.8
finalCalc = calcOne + calcTwo - 15.59
print(finalCalc)
它很大程度上依赖于我发现上面标记为def syllables(word)(上面找到的信用)的一段代码,它显示字符串中的音节数。它可以在某些网站上运行,但是当我在其他网站上运行代码时,我收到以下错误:
Traceback (most recent call last):
File "C:\Users\Waves\Desktop\gradeLevel.py", line 48, in <module>
paraSyll = syllables(para)
File "C:\Users\Waves\Desktop\gradeLevel.py", line 10, in syllables
if word[0] in vowels:
IndexError: string index out of range
据我了解,这可能与 [0] 是数组中的第一个对象有关,而我相信原作者的意思是暗示“如果没有元音分隔符......”,但我'我不确定。如果您对代码有任何不相关的批评,请随时提出。先感谢您!
最佳答案
p
元素中有空文本
for para in paragraphs:
print(para)
# <p class="mw-empty-elt"> </p>
直接跳过
for para in paragraphs:
para = para.text.strip()
if not para:
continue
关于python - 读取关卡脚本在某些站点上发送错误 "IndexError: string index out of range",我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54299366/