这是我现在的代码:
d = {}
for stage in ['doggo', 'floofer', 'puppo', 'pupper']:
#d[stage] =df.groupby([stage]).agg({'retweet_count': 'sum'})
d[stage] = df.groupby(stage)['retweet_count'].sum()
stage_retweets = pd.DataFrame.from_dict(d)
它产生这个:
doggo floofer puppo pupper
None 1387471.0 1517639.0 1472697.0 1444766.0
doggo 159188.0 NaN NaN NaN
floofer NaN 29020.0 NaN NaN
puppo NaN NaN 73962.0 NaN
pupper NaN NaN NaN 101893.0
我真正想要制作的是:
doggo floofer puppo pupper
None 1387471.0 1517639.0 1472697.0 1444766.0
stage 159188.0 29020.0 73962.0 101893.0
有谁知道如何实现这一点吗?
最佳答案
d = {}
# 1 - Put your stages in a list variable
stages = ['doggo', 'floofer', 'puppo', 'pupper']
for stage in stages:
d[stage] = df.groupby(stage)['retweet_count'].sum()
stage_retweets = pd.DataFrame.from_dict(d)
print(stage_retweets)
# 2 - Create a column conditionally to detect if the index in stages list or not
# !! important !! make shure you have only one index level otherwise stage_retweets.index.isin(stages) won't work
stage_retweets['is_stage'] = np.where(stage_retweets.index.isin(stages), 'Stage', 'None')
print(stage_retweets)
# 3 - Groupby this new column
stage_retweets = stage_retweets.groupby('is_stage').sum().reset_index()
print(stage_retweets)
关于Python如何将数据分组为合并数据框?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54727150/