mysql - Doctrine 中的简单 IF 测试语句

Question

Doctrine 是否支持 IF 语句？我收到以下错误:

Expected known function, got 'IF'

在使用 IF 执行此查询时:

$qb->select("c.id, IF(c.type_id LIKE 9, c.name, c.lastname) as name")

用纯 SQL 重写时它工作正常。有什么解决方法吗？

Answer 1

是的 if Doctrine 中的陈述不被支持，您可以将其转换为 case when

IF(c.type_id LIKE 9, c.name, c.lastname) as name

到

case when c.type_id = 9 then c.name else c.lastname end as name

更新: 根据评论，concat 函数在 case-when

中是允许的

答案是肯定的，非常允许。这是一个例子

mysql> select * from timesheets ;
+-----------+-------+----------+
| client_id | hours | category |
+-----------+-------+----------+
|         1 |  1.50 | onsite   |
|         1 |  1.50 | onsite   |
|         1 |  1.00 | remote   |
|         2 |  1.50 | remote   |
+-----------+-------+----------+
4 rows in set (0.00 sec)

mysql> select 
case when category = 'onsite' then concat('ON',' ',hours) else hours
end as dd from timesheets ;
+---------+
| dd      |
+---------+
| ON 1.50 |
| ON 1.50 |
| 1.00    |
| 1.50    |
+---------+
4 rows in set (0.00 sec)