我有列df['Status']
,其中包含一些对象:
在:df.Status.unique()
输出:数组([nan, 'Open', 'Plmt', 'SHRT', 'Check'], dtype=object)
栏目:
在:df['状态']
输出:时间状态
2016-01-15 08:55:00 开放
2016-01-15 09:00:00 计划
2016-01-15 09:05:00 计划
2016-01-15 09:10:00 计划
2016-01-15 09:15:00 计划
2016-01-15 09:20:00 计划
2016-01-15 09:25:00 计划
2016-01-15 09:30:00 计划
2016-01-15 09:35:00 计划
2016-01-15 09:40:00 SHRT
其中时间
是:
df.index = df['时间']
df.index = pd.to_datetime(df.index)
我想跳过我不需要的值('Plmt'、'Check'、'nan'),创建新列 df['Diff'],其中 'Open' 之间的分钟数差异SHRT'
。
我正在尝试这样:
df['状态'][df['状态'] == 'SHRT'] - df['状态'][df['状态'] == '打开']
但在输出中接收 NaN 值:
时间
2016-01-15 08:55:00 南
2016-01-15 09:40:00 南
2016-01-18 08:30:00 南
2016-01-19 14:30:00 南
2016-01-19 14:35:00 南
2016-01-20 11:10:00 南
2016-01-20 11:45:00 南
预期的输出必须如下所示:
时间状态差异
2016-01-15 08:55:00 打开 NaN
2016-01-15 09:40:00 短时间 00:45:00
2016-02-15 10:00:00 打开 NaN
2016-02-15 14:15:00 SHRT 02:15:00
如何获得时间差,有人可以帮忙吗?
最佳答案
用途:
#changed data samples for better sample data
print (df)
time Status
0 2016-01-15 08:55:00 Open
1 2016-01-15 09:00:00 Plmt
2 2016-01-15 09:05:00 SHRT
3 2016-01-15 09:10:00 Plmt
4 2016-01-15 09:15:00 Open
5 2016-01-15 09:20:00 Plmt
6 2016-01-15 09:25:00 SHRT
7 2016-01-15 09:30:00 SHRT
8 2016-01-15 09:35:00 Plmt
9 2016-01-15 09:40:00 SHRT
<小时/>
#filter only Open and SHRT
df1 = df[df['Status'].isin(['Open','SHRT'])].copy()
#convert column to datetimes
df1['time'] = pd.to_datetime(df1['time'])
print (df1)
time Status
0 2016-01-15 08:55:00 Open
2 2016-01-15 09:05:00 SHRT
4 2016-01-15 09:15:00 Open
6 2016-01-15 09:25:00 SHRT
7 2016-01-15 09:30:00 SHRT
9 2016-01-15 09:40:00 SHRT
#filter only rows with Open and next row SHRT
m1 = (df1['Status'] == 'Open') & (df1['Status'].shift(-1) == 'SHRT')
m2 = (df1['Status'].shift() == 'Open') & (df1['Status'] == 'SHRT')
df2 = df1[m1 | m2].copy()
#create difference column and set NaT by condition
df2['Diff'] = df2['time'].diff().mask(df2['Status'] == 'Open')
print (df2)
time Status Diff
0 2016-01-15 08:55:00 Open NaT
2 2016-01-15 09:05:00 SHRT 00:10:00
4 2016-01-15 09:15:00 Open NaT
6 2016-01-15 09:25:00 SHRT 00:10:00
关于python - 按列计算时差 Pandas,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55001770/