python - 如何在 Python 3 中将变量设置为随机整数？

Question

我对编码还比较陌生，现在正在尝试用 Python 3 构建一个石头剪刀布游戏。这是我目前的代码`

answer = input("To play: type in Rock (r), Paper (p) or Scissors (s)").lower()

if answer == "rock" or answer == "r":
    answer = 1
    print ("You chose Rock!")

elif answer == "paper" or answer == "p":
    answer = 2
    print ("You chose Paper!")

elif answer == "scissors" or answer == "s":
    answer = 3
    print ("You chose Scissors!")

else:
    print ("You didn't pick an option... Make sure you spell it right!")
    rps()

computer = lambda: random.randint(1, 3)
if computer == 1:
    string_computer = "Rock"
elif computer == 2:
    string_computer = "Paper"
elif computer == 3:
    string_computer = "Scissors"
else:
    print ("There must had been a glitch")
    rps()

if answer == computer:
    print(("The computer chose"), string_computer,("so it\'s a draw!"))
elif answer == 1 and computer == 2:
    print(("The computer chose"), string_computer,("so unfortuantely you lost."))
    rps()
elif answer == 1 and computer == 3:
    print(("The computer chose"), string_computer,("so you won! Congratulations!"))
    rps()
elif answer == 2 and computer == 1:
    print(("The computer chose"), string_computer,("so you won! Congratulations!"))
    rps()
elif answer == 2 and computer == 3:
    print(("The computer chose"), string_computer,("so unfortuantely you lost."))
    rps()
elif answer == 3 and computer == 1:
    print(("The computer chose"), string_computer,("so unfortuantely you lost."))
    rps()
else:
    print(("The computer chose"), string_computer,("so you won! Congratulations!"))
    rps()

`

当我尝试运行代码时，所有语法都是正确的，但它出现了“一定有一个小故障”，我将其添加进去以查看它是否没有选择 1 到 3 之间的数字。我该如何修复所以它会选择 1 到 3 之间的数字？

Answer 1

import random

computer = random.randint(1,3)

这里不需要 lambda 函数。

将 lambda 函数集 computer 包含为将生成 1 到 3 之间的随机数的函数:

>>> computer = lambda: random.randint(1, 3)
>>> computer
<function <lambda> at 0x000001F4DD2738C8>

如果您随后调用 computer()，您将获得一个 1 到 3 之间的随机数:

>>> computer()
2
>>> computer()
2
>>> computer()
1

对于您的功能来说，摆脱lambda:是最好的解决办法。如果您想在 if computer... 语句中添加括号，则可能会出现 glitch 语句，因为您将为每个生成一个新的随机 int computer() 调用。