java - SQL 错误 : 1064, SQLState:创建新实体时为 42000

Question

我正在开发一个 Spring mvc web 应用程序，我需要在其中使用 Hibernate 创建一个城镇。以下是我的城镇模型。

@Entity
@Table(name="town")
public class TownModel {

    @Id
    @Column(name="townid")
    @GeneratedValue 
    private Integer townId;

    @Column(name="name")
    private String townName;

    @Column(name="desc")
    private String townDesc;

    @ManyToOne(optional = true)
    @JoinColumn(name="districtid")
    private DistrictModel districtModel;
}

我有另一个名为 district 的实体。城镇是地区的一部分，一个地区可以有多个城镇。以下是我的地区模型:

@Entity
@Table(name="district")
public class DistrictModel {

    @Id
    @Column(name="districtid")
    @GeneratedValue
    private Integer districtId;

    @Column(name="name")
    private String name;

    @Column(name="desc")
    private String description;

    @OneToMany(mappedBy = "districtModel", fetch = FetchType.EAGER)
    @Fetch(value = FetchMode.SUBSELECT)
    private List<TownModel> townModelList;
}

我正在使用以下 Hibernate 代码来拯救城镇:

Session session = sessionFactory.getCurrentSession();
session.save(townModel);

但是显示错误:

21:22:08,104 WARN  [org.hibernate.engine.jdbc.spi.SqlExceptionHelper] (http--127.0.0.1-9090-1) SQL Error: 1064, SQLState: 42000
21:22:08,112 ERROR [org.hibernate.engine.jdbc.spi.SqlExceptionHelper] (http--127.0.0.1-9090-1) You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'desc, name) values (2, 'Test town desc.', 'Test town')' at line 1

com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'desc, name) values (2, 'Test town desc.', 'Test town')' at line 1
    at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) ~[na:1.7.0_45]
    at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:57) ~[na:1.7.0_45]
    at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:45) ~[na:1.7.0_45]
    at java.lang.reflect.Constructor.newInstance(Constructor.java:526) ~[na:1.7.0_45]
    at com.mysql.jdbc.Util.handleNewInstance(Util.java:377) ~[com.mysql.jdbc_5.1.5.jar:na]
    at com.mysql.jdbc.Util.getInstance(Util.java:360) ~[com.mysql.jdbc_5.1.5.jar:na]
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:978) ~[com.mysql.jdbc_5.1.5.jar:na]
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3887) ~[com.mysql.jdbc_5.1.5.jar:na]
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3823) ~[com.mysql.jdbc_5.1.5.jar:na]
    at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:2435) ~[com.mysql.jdbc_5.1.5.jar:na]
    at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2582) ~[com.mysql.jdbc_5.1.5.jar:na]
    at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2530) ~[com.mysql.jdbc_5.1.5.jar:na]
    at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:1907) ~[com.mysql.jdbc_5.1.5.jar:na]
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2141) ~[com.mysql.jdbc_5.1.5.jar:na]
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2077) ~[com.mysql.jdbc_5.1.5.jar:na]
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2062) ~[com.mysql.jdbc_5.1.5.jar:na]
    at org.jboss.jca.adapters.jdbc.WrappedPreparedStatement.executeUpdate(WrappedPreparedStatement.java:493) ~[na:na]
    at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.executeUpdate(ResultSetReturnImpl.java:186) ~[hibernate-core-4.2.16.Final.jar:4.2.16.Final]
    ... 64 common frames omitted

Answer 1

错误消息指出:

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'desc, name) values (2, 'Test town desc.', 'Test town')' at line 1

问题出在生成的查询中，因为使用了 desc，因为它是 MySQL 中的保留字。

可能的解决方案:

1. 将您的列名称更改为description。对 name 做类似的事情。
2. 更改 MySQL 中的配置以支持查询中列的此类名称。

3. 更改字段中列的名称以附加 ` 字符(引用自 Creating field with reserved word name with JPA ):

   @Column(name="`desc`")
   

IMO 虽然选项 3 是一个快速而肮脏的解决方案，但我发现选项 1 是 future 使用数据库的最佳解决方案。