python - 停止 Pygame 中的多个键盘输入

Question

我有一些 python 代码，它使用 pygame 窗口来确定按下的键。当按下一个键时，代码会开始执行一些操作，然后返回查看下一个按下的键可能是什么。

我遇到的问题是，如果用户重复按下某个键，即使“代码开始执行操作”，pygame 似乎也会记住按下的内容，而不是等待下一次按键。我想要的是让代码在“开始做事情”完成时忽略任何按键，然后一旦完成，就得到下一个按键。希望这是有道理的!

import pygame
import time

pygame.init()

screen = pygame.display.set_mode((450,282))
screen.fill((0,0,0))
pygame.display.flip()
clock = pygame.time.Clock()
done = False

def go_and_do_things():
    print("doing things")
    time.sleep(2)
    print("things done")

# Loop as long as done == False
while not done:    
    for event in pygame.event.get():  # User did something
        if event.type == pygame.KEYDOWN:
            keypressedcode = event.key # This is the ASCII code
            print("keypressedcode is " + str(keypressedcode))
            go_and_do_things()


        elif event.type == pygame.QUIT:  # If user clicked close
            done = True  # Flag that we are done so we exit this loop

    clock.tick(60)

time.sleep(4)
pygame.quit()

Answer 1

您可以使用pygame.event.clear 。如下所示，它将在 go_and_do_things() 期间丢弃所有按键。

while not done:    
    for event in pygame.event.get():  # User did something

         # Any key down
        if event.type == pygame.KEYDOWN:

            keypressedcode = event.key # This is the ASCII code
            print("keypressedcode is " + str(keypressedcode))

            go_and_do_things()
            pygame.event.clear(eventtype=[pygame.KEYDOWN,
                                          pygame.KEYUP)


        elif event.type == pygame.QUIT:  # If user clicked close
            done = True  # Flag that we are done so we exit this loop

    clock.tick(60)