python - 存储由数据帧组成的字典的最有效方法

Question

我有一本包含数据帧的字典。

dictionary = {"key1": df1,
              "key2": df2, and so on...}

很少有 stackoverflow 帖子和 reddit 建议使用 Json 模块和 pickle 模块。

最有效的方法是什么？为什么？

当我将小字典转换为 pickle 时，它​​的内存小于 0kb，并且呈现 EOFError: Ran out of input ，解释如下 Why do I get "Pickle - EOFError: Ran out of input" reading an empty file?

Answer 1

当您喜欢紧凑的文件格式时，我建议使用 pickle。

# import packages
import pandas as pd
import numpy as np
import pickle
import os

# create dictionary of dataframes
nrows, ncols, ndataframes = 1_000, 50, 100
my_dict = {k:v for (k,v) in [[f'df_{n}', pd.DataFrame(np.random.rand(nrows, ncols))] for n in range(ndataframes)]}

# save dictionary as pickle file
pickle_out = open('my_dict.pickle', 'wb')
pickle.dump(my_dict, pickle_out)
pickle_out.close()

# create new dictionary from pickle file
pickle_in = open('my_dict.pickle', 'rb')
new_dict = pickle.load(pickle_in)

# print file size
print('File size pickle file is', round(os.path.getsize('my_dict.pickle') / (1024**2), 1), 'MB')

# sample
new_dict['df_10'].iloc[:5, :5]

结果:

pickle 文件的文件大小为 38.2 MB

          0         1         2         3         4
0  0.338838  0.501158  0.406240  0.693233  0.567305
1  0.092142  0.569312  0.952694  0.083705  0.006950
2  0.684314  0.373091  0.550300  0.391419  0.877889
3  0.117929  0.597653  0.726894  0.763094  0.466603
4  0.530755  0.472033  0.553457  0.863435  0.906389