您好，我是 Django 新手，我正在尝试构建一个网站。 在管理页面http://127.0.0.1:8000/admin/posts/post/我添加了两个帖子，每个帖子都有一个鼻涕虫，**第一个鼻涕虫是第一个，第二个是第二个 问题是当我尝试到达 http://127.0.0.1:8000/posts/first 时或http://127.0.0.1:8000/posts/second它给了我一个 404 错误，它告诉我**
Using the URLconf defined in custom.urls, Django tried these URL patterns, in this order:
admin/ posts/ [name='posts_list'] <slug>The current path, posts/first, didn't match any of these.
这是 models.py
from django.db import models
from django.conf import settings
Create your models here.
User = settings.AUTH_USER_MODEL
class Author(models.Model):
user = models.ForeignKey(User, on_delete=models.CASCADE)
email = models.EmailField()
phone_num = models.IntegerField(("Phone number"))
def __str__(self):
return self.user.username
class Post(models.Model):
title = models.CharField(max_length=120)
description = models.TextField()
slug = models.SlugField()
image = models.ImageField()
author = models.OneToOneField(Author, on_delete=models.CASCADE)
def __str__(self):
return self.title
这是views.py
from django.shortcuts import render, get_object_or_404
from .models import Post
# Create your views here.
def posts_list(request):
all_posts = Post.objects.all()
return render(request,
"posts/posts_list.html",
context = {"all_posts": all_posts})
def posts_detail(request, slug):
unique_slug = get_object_or_404(Post, slug = slug)
return render(request, "posts/posts_detail.html", {"post": unique_slug})
这是 urls.py
from django.contrib import admin
from django.urls import path
from posts.views import posts_list, posts_detail
urlpatterns = [
path('admin/', admin.site.urls),
path("posts/", posts_list, name = "posts_list"),
path("<slug>", posts_detail), #, name = "unique_slug"
]
这就是模板: posts_list.html
<!DOCTYPE html>
<html>
<head>
<title>
</title>
</head>
<body>
{{ all_posts }}
</body>
</html>
post_detail.html
<!DOCTYPE html>
<html>
<head>
<title>
</title>
</head>
<body>
{{ post }}
</body>
</html>
最佳答案
一个slug从不包含斜线。您的网址似乎带有 posts/ 前缀。所以你可以改变你的 urls.py与:
from django.contrib import admin
from django.urls import path
from posts.views import posts_list, posts_detail
urlpatterns = [
path('admin/', admin.site.urls),
path('posts/', posts_list, name='posts_list'),
path(<b>'posts/<slug:slug>/'</b>, posts_detail, name='unique_slug'),
]最好添加路径转换器的类型，因此 <<b>slug:</b>slug> .
您可能想使用 django-autoslug [GitHub]根据特定字段自动构建 slug。
关于python - 如何在 Django 中正确使用 slug url？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/59535275/