python - Ursina 模块中的 invoke() 做了什么

Question

我导入了Ursina module 。它是一个游戏引擎。

我查找了一个教程，在代码中使用了 invoke() 。我尝试查找文档，但似乎没有相关信息。本教程中的代码如下:

from ursina import *

# create a window
app = Ursina()

# most things in ursina are Entities. An Entity is a thing you place in the world.
# you can think of them as GameObjects in Unity or Actors in Unreal.
# the first paramenter tells us the Entity's model will be a 3d-model called 'cube'.
# ursina includes some basic models like 'cube', 'sphere' and 'quad'.

# the next parameter tells us the model's color should be orange.

# 'scale_y=2' tells us how big the entity should be in the vertical axis, how tall it should be.
# in ursina, positive x is right, positive y is up, and positive z is forward.

player = Entity(model='cube', color=color.orange, scale_y=2)

# create a function called 'update'.
# this will automatically get called by the engine every frame.

def update():
    player.x += held_keys['d'] * time.dt
    player.x -= held_keys['a'] * time.dt

# this part will make the player move left or right based on our input.
# to check which keys are held down, we can check the held_keys dictionary.
# 0 means not pressed and 1 means pressed.
# time.dt is simply the time since the last frame. by multiplying with this, the
# player will move at the same speed regardless of how fast the game runs.


def input(key):
    if key == 'space':
        player.y += 1
        invoke(setattr, player, 'y', player.y-1, delay=.25)


# start running the game
app.run()

请帮助我。

附注我正在使用 Linux Mint。

Answer 1

用于延迟调用函数，类似于Unity中的Invoke()。因此在这种情况下，0.25 秒后，player.y 会减少 1。

调用(函数，*args，**kwargs)

编辑:文档中的示例:

def test_func(item, x=None, y=None):
    print(item, x, y)

test_func('test')
invoke(test_func, 'test', delay=.1)
invoke(test_func, 'test1', 1, 2, delay=.2)
invoke(test_func, 'test2', x=1, y=2, delay=.3)`