Python凯撒Cypher助力一个级别

Question

有人可以帮我弄清楚如何将加密句子的所有字母保留在同一行上。该代码可以工作，尽管很长哈。

sentence = raw_input('Enter a sentence to be encrypted ')
shift = input('Enter a shift value ')

def createDict (shift):
    alphabet = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ .,'
    alphaList=[]

    for letter in alphabet:
        alphaList.append(letter)
    alphaDict={}
    for letter in alphaList:
        valueLetterIndex = (alphaList.index(letter) + shift)%len(alphaList)
        valueLetter = alphaList[valueLetterIndex]
        alphaDict[letter] = valueLetter
    return alphaDict

def encryptText(sentence, shift):
    dict = createDict(shift)
    for letter in sentence:
        encryptC = dict [letter]
        print encryptC

print encryptText(sentence, shift)

Answer 1

收集列表中的加密字符，然后打印连接结果:

def encryptText(sentence, shift):
    encryptionmap = createDict(shift)
    output = []
    for letter in sentence:
        output.append(encryptionmap[letter])
    print ''.join(output)

我将您的 dict 变量重命名为 map 以避免屏蔽内置 dict 类型。

您的createDict函数可以简化为:

def createDict (shift):
    alphabet = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ .,'

    alphaDict = {}
    for pos, letter in enumerate(alphabet):
        valueLetterIndex = (pos + shift) % len(alphabet)
        valueLetter = alphabet[valueLetterIndex]
        alphaDict[letter] = valueLetter
    return alphaDict

因为字符串就像列表一样是一个序列；无需先转换为列表。通过使用enumerate，我们省去了查找每个字母索引的麻烦。