python - 过滤数据并按编号排序显示结果。职位的

Question

在 Django 中，我需要过滤数据并显示结果，如下所示。例如

Company3(20)
Company1(12)
Company2(3)

这里“Company1,Company2,Company3”是公司名称，括号内的“20,12,3”是公司名称。特定公司发布的职位。

models.py

class User(models.Model):
     first_name= forms.CharField(max_length=30,widget=forms.TextInput())
     last_name = forms.CharField(max_length=30,widget=forms.TextInput())
     username = forms.CharField(max_length=30,widget=forms.TextInput())
     email = forms.EmailField(widget=forms.TextInput())
     password = forms.CharField(widget=forms.PasswordInput())
     companyname = forms.CharField(max_length=30,widget=forms.TextInput())

class jobs(models.Model):
     emp = models.ForeignKey(User, unique=False)
     title = models.CharField(max_length=30)
     referencecode = models.CharField(max_length=30)
     jobsummary = models.TextField()
     jobdetails = models.TextField()
     key_skills = models.CharField(max_length=30)

我试图给出views.py就像

def search_result(request):

     details=User.objects.filter(jobs__isnull=False).select_related()
     return render_to_response('searchresult.html', {'details': details})

templates
<ul>
{% for d1 in details %}
<li>{{ d1.companyname }}({{ d1.count }})</li>
{% endfor %}
</ul>

给出一些想法来显示如上所示的结果

Answer 1

也许更高效的看起来像

details = User.objects.filter(jobs__isnull=False).annotate(job_count=Count('jobs'))\
                   .order_by('job_count')

然后在模板中

<ul>
{% for d1 in details %}
    <li>{{ d1.companyname }}({{ d1.job_count }})</li>
{% endfor %}
</ul>