我正在尝试将行插入到具有三个表的数据库中:
- 艺术家
- 歌曲
- 媒体(例如 YouTube 视频)
艺术家与歌曲具有一对多关系,歌曲与媒体具有一对多关系。当艺术家、歌曲和媒体都是新的并且需要添加到数据库中时,我就会陷入困境。
我想我可以添加艺术家,提交它,然后检索艺术家对象,然后使用艺术家对象添加歌曲,将相同的想法应用于歌曲>媒体。但这似乎不是最有效的方法。
我尝试先添加每个对象,然后在最后提交:
new_artist = models.Artist(
name = artist_name,
)
db.session.add(artist)
new_song = models.Song(
name = song_name,
artist = artist,
)
db.session.add(song)
new_media = models.Media(
song = song,
media_id = media_id,
user=user
)
db.session.add(media)
db.session.commit()
但我收到此错误:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/path/python2.7/site-packages/sqlalchemy/orm/scoping.py", line 114, in do
return getattr(self.registry(), name)(*args, **kwargs)
File "/path/python2.7/site-packages/sqlalchemy/orm/session.py", line 703, in commit
self.transaction.commit()
File "/path/python2.7/site-packages/sqlalchemy/orm/session.py", line 361, in commit
self._prepare_impl()
File "/path/python2.7/site-packages/sqlalchemy/orm/session.py", line 340, in _prepare_impl
self.session.flush()
File "/path/python2.7/site-packages/sqlalchemy/orm/session.py", line 1718, in flush
self._flush(objects)
File "/path/python2.7/site-packages/sqlalchemy/orm/session.py", line 1789, in _flush
flush_context.execute()
File "/path/python2.7/site-packages/sqlalchemy/orm/unitofwork.py", line 331, in execute
rec.execute(self)
File "/path/python2.7/site-packages/sqlalchemy/orm/unitofwork.py", line 475, in execute
uow
File "/path/python2.7/site-packages/sqlalchemy/orm/persistence.py", line 64, in save_obj
table, insert)
File "/path/python2.7/site-packages/sqlalchemy/orm/persistence.py", line 558, in _emit_insert_statements
execute(statement, params)
File "/path/python2.7/site-packages/sqlalchemy/engine/base.py", line 1449, in execute
params)
File "/path/python2.7/site-packages/sqlalchemy/engine/base.py", line 1584, in _execute_clauseelement
compiled_sql, distilled_params
File "/path/python2.7/site-packages/sqlalchemy/engine/base.py", line 1698, in _execute_context
context)
File "/path/python2.7/site-packages/sqlalchemy/engine/base.py", line 1691, in _execute_context
context)
File "/path/python2.7/site-packages/sqlalchemy/engine/default.py", line 331, in do_execute
cursor.execute(statement, parameters)
sqlalchemy.exc.InterfaceError
关于如何实现这一目标有什么想法吗?
最佳答案
你能试试这个,并让我知道你得到了什么吗?
基本上,我只是输入了正确的引用变量。
new_artist = models.Artist(
name = artist_name,
)
db.session.add(new_artist)
new_song = models.Song(
name = song_name,
artist = new_artist,
)
db.session.add(new_song)
new_media = models.Media(
song = new_song,
media_id = media_id,
user=user
)
db.session.add(new_media)
db.session.commit()
关于python - 使用 SQLAlchemy ORM 将新的一对多数据插入表中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16409353/