所以我有这个:
z='===hello
there===,
how are ===you===?'
我想成为:
z='<b>hello
there<\b>,
how are <b>you<\b>?'
我尝试这样做:
z = re.sub(r"\={3}([^\$]+)\={3}", r"<b> \\1 </b>", z, re.M)
它确实有效，但我得到了这个:
z='<b>hello
there===,
how are ===you<\b>?'
我对此还很陌生，但我相信是 ^ 和 $ 使其匹配字符串的开头和结尾。那么我该如何更改它以使其与中间的相匹配呢？
最佳答案
re.sub(r"\={3}([^\$]+?)\={3}", r"<b> \\1 </b>", z, re.M)
从 python 文档复制 Click Here :
*?, +?, ?? The '*', '+', and '?' qualifiers are all greedy; they match as much text as possible. Sometimes this behaviour isn’t desired; if the RE <.*> is matched against '<H1>title</H1>', it will match the entire string, and not just '<H1>'. Adding '?' after the qualifier makes it perform the match in non-greedy or minimal fashion; as few characters as possible will be matched. Using .*? in the previous expression will match only '<H1>'.
关于python - 正则表达式多行替换，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/16516093/