python - 为什么我收到错误 'exceptions.ValueError: too many values to unpack' ？

Question

我有以下字典，它是从 XHR 请求生成的 json 对象，其中字典键由元组组成:

{(u'goal', u'corner', u'rightfoot'): 1, (u'goal', u'openplay', u'rightfoot'): 3, (u'miss', 
    u'corner', u'header'): 8, (u'goal', u'corner', u'header'): 1, (u'goal', u'openplay', u'leftfoot'): 2,
     (u'miss', u'openplay', u'rightfoot'): 30, (u'miss', u'corner', u'rightfoot'): 2, (u'miss', 
    u'crossedfreekick', u'header'): 3, (u'goal', u'penalty', u'rightfoot'): 1, (u'miss', u'fastbreak', 
    u'rightfoot'): 2, (u'miss', u'crossedfreekick', u'rightfoot'): 3, (u'goal', u'openplay', u'header'): 
    1, (u'goal', u'crossedfreekick', u'rightfoot'): 1, (u'miss', u'openplay', u'header'): 2, (u'goal', 
    u'crossedfreekick', u'header'): 1, (u'miss', u'openplay', u'leftfoot'): 22, (u'miss', 
    u'directfreekick', u'rightfoot'): 1, (u'miss', u'crossedfreekick', u'leftfoot'): 1}

我使用以下代码对上面字典中的值进行有条件求和:

goal1 = {"'goal','openplay','leftfoot'", "'goal','openplay','rightfoot'", "'goal','openplay','header'", "'goal','openplay','otherbodypart'"}
                            regex1 = sum(int(value) for key, value in regex if key in goal1)

但是，这会产生以下错误消息:

regex1 = sum(int(value) for key, value in regex if key in goal1)
    exceptions.ValueError: too many values to unpack

任何人都可以向我解释为什么这是和/或更正替代语法吗？

谢谢

Answer 1

regex1 = sum(int(value) for key, value in regex.items() if key in goal1)

您需要使用包含键和值的dict.items，循环遍历您仅迭代键的regex字典，这样您就无法解压键以及由此产生的错误值。

键也是元组，因此您需要将键作为元组存储在goal1中:

goal1 = {('goal','openplay','leftfoot'), ('goal','openplay','rightfoot'), ('goal','openplay','header'), ('goal','openplay','otherbodypart')}


print(regex1)
6