python 元组返回 datetime.datetime

Question

问题:

每当我得到以下查询的结果时:

"SELECT email, url, `timestamp` FROM `transaction` WHERE `email` != '' AND `timestamp` >= \'" + dateonlystring + "\' AND `timestamp` < DATE(DATE_ADD(\'" + dateonlystring + "\', INTERVAL 1 DAY))"

这出现了:

(' [email protected] ', ' http://sample.url.com ', datetime.datetime(2015, 2, 25, 10, 11, 19))

为什么是 datetime.datetime(2015, 2, 25, 10, 11, 19))？

我怎样才能把它变成这样:

[email protected] ~ http://sample.url.com~2015-02-25 10:11:19

我的代码/我尝试过的内容:

#Date
#datestamp = datetime.strptime('2015-02-25 00:00:00', "%Y-%m-%d %H:%M:%S")
datestamp = datetime.now()
dateonlystring = str(datestamp.date().strftime("%Y-%m-%d %H:%M:%S"))
datetimestring = str(datestamp.now().strftime("%Y%m%d%H%M%S"))

#Dunchangeme:
#Query:
q_getstuff = "SELECT email, url, `timestamp` FROM `transaction` WHERE `email` != '' AND `timestamp` >= \'" + dateonlystring + "\' AND `timestamp` < DATE(DATE_ADD(\'" + dateonlystring + "\', INTERVAL 1 DAY))"

try:
    con = mdb.connect(hostname, username, password, database)
    cur = con.cursor()
    cur.execute(q_getstuff)
    result = cur.fetchall()

    for row in result:
        tuplecrap = str(row).replace('(', '').replace(')', '').replace('\'', '').replace(', ', '~')
        print tuplecrap

值得注意的是，如果用户打算前往特定日期(而不是现在)，则注释的第一个 datestamp 就会出现。

最简单的方法是简单地去掉括号和逗号，就像我上面所做的那样，但是如果不使用复杂的正则表达式解决方案，这并不能解决问题，而且我很确定这不是正确的方法。

有什么建议吗？

Answer 1

您有每个结果行包含 3 个项目的元组，只需将其解压即可:

for row in result:
    email, url, date = row
    # here you can format date as you want