有人可以解释一下为什么我无法获得第二个索引(传入)的总和。我尝试在第一次迭代之后打印变量 group 的值,似乎一旦迭代就不再有值了。
我从这个例子中获取了一些代码。 example post
products = {}
products['product']= [ {
'id':1234,
'stock_id':1001,
'lot_id':5001,
'name':'product1',
'qty':50,
'incoming':100,
}
.................
.................
]
grouper = itemgetter("id","stock_id","lot_id")
result = []
for key, group in groupby(sorted(products['product'], key= grouper),grouper):
temp_dict= dict(zip(["id","stock_id","lot_id"], key))
temp_dict["qty"] = sum(item["qty"] for item in group)
temp_dict["incoming"] = sum(item["incoming"] for item in group)
result.append(temp_dict)
for r in result:
print r
结果
{'lot_id': 5001, 'stock_id': 1001, 'incoming': 0, 'id': 1234, 'qty': 250}
{'lot_id': 5001, 'stock_id': 1001, 'incoming': 0, 'id': 1235, 'qty': 50}
{'lot_id': 5002, 'stock_id': 1001, 'incoming': 0, 'id': 1235, 'qty': 100}
{'lot_id': 5001, 'stock_id': 1002, 'incoming': 0, 'id': 1236, 'qty': 100}
最佳答案
您在第一个和中使用组迭代器,在组group = list(group)
上调用list将内容存储在列表中,以便您可以使用它们两次:
for key, group in groupby(sorted(products['product'], key=grouper), grouper):
temp_dict = dict(zip(["id", "stock_id", "lot_id"], key))
group = list(group)
temp_dict["qty"] = sum(item["qty"] for item in group)
temp_dict["incoming"] = sum(item["incoming"] for item in group)
你基本上在做:
In [4]: group = iter([1,2,3,4])
In [5]: for ele in group: # iterator will be consumed
print(ele)
...:
1
2
3
4
In [6]: for ele in group: # nothing left to iterate
print(ele)
...:
In [7]:
关于Python 按两列或更多列进行分组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30355624/