Python subprocess.popen 返回空字符串

Question

import subprocess
cd=['sudo','./interface','-a','</tmp/vol.js']
p = subprocess.Popen(cd, stdout = subprocess.PIPE,stderr=subprocess.PIPE, stdin=subprocess.PIPE)

上面的代码返回 null，但是当我运行相同的命令时，即 sudo ./interface -a </tmp/vol.js工作完全正常

Answer 1

你能试试这个吗？

import subprocess
cd = ['sudo','./interface','-a','</tmp/vol.js']
cd_cmd = " ".join(cd)
o, e = subprocess.Popen(cd, shell=True, stdout=subprocess.PIPE, stderr=subprocess.PIPE).communicate()

输出存储在变量“o”中，stderr 存储在“e”中