python - 使用 termcolor.colored 打印某些字符串不同的颜色？

Question

我想在Python中以不同的颜色打印某些字符串。我需要修改代码:

board_p1 = []
board_pc = []

board_size=6

for x in range(board_size):
    board_p1.append(["[W]"] * board_size)
    board_pc.append(["[W]"] * board_size)

def print_board(board):
    if board == board_p1:
        print colored("\n   Computers Board:    ",attrs=['underline'])
        for row in board:
            print " ".join(colored(element,"cyan") if element != "[X]" else colored(element,"red") if element != "[H]" else colored(element,"magenta") for element in row)
    if board == board_pc:
        print colored("\n    Players Board:     ",attrs=['underline'])
        for row in board_pc:
            print " ".join(colored(element,"cyan") if element != "[S]" else colored(element,"green") if element != "[X]" else colored(element,"red") if element != "[H]" else colored(element,"magenta") for element in row)

这样，当在列表中时，[H] 将打印为洋红色，[X] 将打印为红色，等等，我可以得到如下输出:

我遇到困难:

print " ".join(colored(element,"cyan") if element != "[S]" else colored(element,"green") if element != "[X]" else colored(element,"red") if element != "[H]" else colored(element,"magenta") for element in row)

以便以上述方式打印。

问:如何修改/编辑上面的代码行，以便在列表中看到 [X] 时将其打印为红色，[S] 打印为绿色，[H] ] 洋红色？

Answer 1

尽管由于添加了括号，以下内容可以正确解析:

print " ".join(colored(element,"cyan") if element != "[S]" else (colored(element,"green") if element != "[X]" else (colored(element,"red") if element != "[H]" else colored(element,"magenta"))) for element in row)

但是，由于否定条件，我无法判断它是否会产生您问题中的示例中描述和描述的映射。

但是根据该描述，我建议最好使用这样的字典:

element_colors = {'[W]': 'cyan', '[X]': 'red', '[S]': 'green', '[H]': 'magenta'}

print " ".join(colored(element, element_colors[element]) for element in row)